Answer:
he looks 5
Step-by-step explanation:
he just does hdhdhdjdjdjjdjsmsksjxjchdjdjjdjdjdjdjdjdjdkkd
79.30 ---- 100%
The while store is discounted by 12% So subract 12 from 100
100-12 = 98
We have to figure out what 88% is
79.30 ---- 100%
X ------------ 88%
Cross Multiply
79.3× 88 = 100x
6978.4 = 100X
69.784 is without taxes
69.784 = 100% {100% because it is the total price.}
69.784 = 100%
X --------- 6.25%
Cross Multiply
69.784 × 6.25 = 100X
436.15 = 100 X
X = 4.3615
69.784 + 4.3615
74.15 is the answer
Answer:
(-1-48i) is your answer.........
Answer:
![4x+8:\quad 4\left(x+2\right)](https://tex.z-dn.net/?f=4x%2B8%3A%5Cquad%204%5Cleft%28x%2B2%5Cright%29)
![\:6x-3:\quad 3\left(2x-1\right)](https://tex.z-dn.net/?f=%5C%3A6x-3%3A%5Cquad%203%5Cleft%282x-1%5Cright%29)
Step-by-step explanation:
![4x+8](https://tex.z-dn.net/?f=4x%2B8)
![\mathrm{Rewrite\:}8\mathrm{\:as\:}4\cdot \:2](https://tex.z-dn.net/?f=%5Cmathrm%7BRewrite%5C%3A%7D8%5Cmathrm%7B%5C%3Aas%5C%3A%7D4%5Ccdot%20%5C%3A2)
![=4x+4\cdot \:2](https://tex.z-dn.net/?f=%3D4x%2B4%5Ccdot%20%5C%3A2)
![\mathrm{Factor\:out\:common\:term\:}4](https://tex.z-dn.net/?f=%5Cmathrm%7BFactor%5C%3Aout%5C%3Acommon%5C%3Aterm%5C%3A%7D4)
![=4\left(x+2\right)](https://tex.z-dn.net/?f=%3D4%5Cleft%28x%2B2%5Cright%29)
![6x-3](https://tex.z-dn.net/?f=6x-3)
![\mathrm{Rewrite\:}6\mathrm{\:as\:}3\cdot \:2](https://tex.z-dn.net/?f=%5Cmathrm%7BRewrite%5C%3A%7D6%5Cmathrm%7B%5C%3Aas%5C%3A%7D3%5Ccdot%20%5C%3A2)
![=3\cdot \:2x-3](https://tex.z-dn.net/?f=%3D3%5Ccdot%20%5C%3A2x-3)
![\mathrm{Factor\:out\:common\:term\:}3](https://tex.z-dn.net/?f=%5Cmathrm%7BFactor%5C%3Aout%5C%3Acommon%5C%3Aterm%5C%3A%7D3)
![=3\left(2x-1\right)](https://tex.z-dn.net/?f=%3D3%5Cleft%282x-1%5Cright%29)
Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)
You should already know this:
1.
![\boxed{\bf{\huge{tan \theta = \frac{sin \theta}{cos \theta}}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbf%7B%5Chuge%7Btan%20%5Ctheta%20%3D%20%5Cfrac%7Bsin%20%5Ctheta%7D%7Bcos%20%5Ctheta%7D%7D%7D%7D%3Cspan%3E)
2.
![\boxed{\bf{\huge{cot\theta =\frac{1}{tan\theta}}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbf%7B%5Chuge%7Bcot%5Ctheta%20%3D%5Cfrac%7B1%7D%7Btan%5Ctheta%7D%7D%7D%7D)
3.
![\boxed{\bf{\huge{sin^2\theta +cos^2 \theta = 1}}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbf%7B%5Chuge%7Bsin%5E2%5Ctheta%20%2Bcos%5E2%20%5Ctheta%20%3D%201%7D%7D%7D%7D)
<span>So, our question is:
</span>
![\sf{\huge{tan\theta + cot\theta=\frac{1}{sin\theta cos\theta}}}](https://tex.z-dn.net/?f=%5Csf%7B%5Chuge%7Btan%5Ctheta%20%2B%20cot%5Ctheta%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%7D%7D)
Plug in the first two identities I gave you.
![\sf{\frac{sin\theta}{cos\theta} +\frac{1}{tan\theta} =\frac{1}{sin\theta cos\theta}](https://tex.z-dn.net/?f=%5Csf%7B%5Cfrac%7Bsin%5Ctheta%7D%7Bcos%5Ctheta%7D%20%2B%5Cfrac%7B1%7D%7Btan%5Ctheta%7D%20%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D)
Apply the first identity I said you needed to know on 1/(tan θ). We should get:
![\sf{\frac{sin\theta}{cos\theta} +\frac{1}{\frac{sin\theta}{cos\theta}} =\frac{1}{sin\theta cos\theta}}\\\\\\\sf{\frac{sin\theta}{cos\theta} +\frac{cos\theta}{sin\theta} =\frac{1}{sin\theta cos\theta}](https://tex.z-dn.net/?f=%5Csf%7B%5Cfrac%7Bsin%5Ctheta%7D%7Bcos%5Ctheta%7D%20%2B%5Cfrac%7B1%7D%7B%5Cfrac%7Bsin%5Ctheta%7D%7Bcos%5Ctheta%7D%7D%20%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%7D%5C%5C%5C%5C%5C%5C%5Csf%7B%5Cfrac%7Bsin%5Ctheta%7D%7Bcos%5Ctheta%7D%20%2B%5Cfrac%7Bcos%5Ctheta%7D%7Bsin%5Ctheta%7D%20%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D)
Multiply the first fraction by sinθ, on both the numerator and denominator.
Multiply the second fraction by cos<span>θ, on both the numerator and denominator.
</span>
![\sf{\frac{sin\theta \times sin\theta}{cos\theta \times sin\theta} +\frac{cos\theta \times cos\theta}{sin\theta \times cos\theta} =\frac{1}{sin\theta cos\theta}}\\\\\\ \sf{\frac{sin^2\theta}{sin\theta cos\theta} + \frac{cos^2 \theta}{sin\theta cos\theta} = \frac{1}{sin\theta cos\theta}}\\\\\\\sf\frac{sin^2\theta + cos^2\theta}{sin\theta cos\theta} =\frac{1}{sin\theta cos\theta}}](https://tex.z-dn.net/?f=%5Csf%7B%5Cfrac%7Bsin%5Ctheta%20%5Ctimes%20sin%5Ctheta%7D%7Bcos%5Ctheta%20%5Ctimes%20sin%5Ctheta%7D%20%2B%5Cfrac%7Bcos%5Ctheta%20%5Ctimes%20cos%5Ctheta%7D%7Bsin%5Ctheta%20%5Ctimes%20cos%5Ctheta%7D%20%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%7D%5C%5C%5C%5C%5C%5C%20%5Csf%7B%5Cfrac%7Bsin%5E2%5Ctheta%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%20%2B%20%5Cfrac%7Bcos%5E2%20%5Ctheta%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%20%3D%20%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%7D%5C%5C%5C%5C%5C%5C%5Csf%5Cfrac%7Bsin%5E2%5Ctheta%20%2B%20cos%5E2%5Ctheta%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%20%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%7D)
Now, use the third identity I said that you needed to know to simplify the numerator.
![\sf{\frac{sin^2\theta +cos^2\theta}{sin\theta cos\theta} =\frac{1}{sin\theta cos\theta}}\\\\\\\sf{\frac{1}{sin\theta cos\theta}=\frac{1}{sin\theta cos\theta}}](https://tex.z-dn.net/?f=%5Csf%7B%5Cfrac%7Bsin%5E2%5Ctheta%20%2Bcos%5E2%5Ctheta%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%20%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%7D%5C%5C%5C%5C%5C%5C%5Csf%7B%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%3D%5Cfrac%7B1%7D%7Bsin%5Ctheta%20cos%5Ctheta%7D%7D)
LHS = RHS
<span>
Therefore, identity is verified.</span>