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3 years ago

What's the product of 21 and (6.3 times 10-4)

1 answer:

3 0

21(6.3 x 10 - 4). Remember PEMDAS. Everything done in parenthesis is done first.

Within the parenthesis, there is multiplication and subtraction. In PEMDAS, multiplication/division comes before addition/subtraction, so 6.3 x 10 = 63.
63 - 4 = 59
21(59) = 1,239.

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for v= 4i - 5j, find unit vector u in the direction of v, and write your answer as a linear combination of the standard unit vec

umka21 [38]

Answer:

a. $u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

Step-by-step explanation:

The given vector is v= 4i - 5j

The magnitude of this vector is;

$|v|=\sqrt{(-4)^2+(-5)^2}$

$|v|=\sqrt{16+25}$

$|v|=\sqrt{41}$

The unit vector u in the direction of v is;

$u=\frac{v}{|v|}$

$u=\frac{4i - 5j}{\sqrt{41}}$

$u=\frac{4i }{\sqrt{41}}-\frac{5j}{\sqrt{41}}$

We rationalize to get

$u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

4 0

3 years ago

Read 2 more answers

A blue whale calf weighed 2725 kilograms at birth. A blue whale calf gains 90 kilograms of weight each day for the first 240 day

Ivanshal [37]

Answer:the weight after 225 days is

22885 kilograms

Step-by-step explanation:

The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.

The formula for the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

n is the number of terms of the sequence.

a is the first term

d is the common difference

We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225

Therefore

T225 = 2725 + (225 - 1)90

T225 = 2725 + 224×90 = 2725 + 20160

T225 = 22885

8 0

3 years ago

A pile of 10 000 paper is 89 cm thick. How thick is one sheet of paper?

Iteru [2.4K]

Answer:

0.0089 cm

Step-by-step explanation:

89/10 000

=0.0089

8 0

3 years ago

A presidential candidate plans to begin her campaign by visiting the capitals in 44 of 5050 states. what is the probability that

defon

Part A:

Given that A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 50 states.

The number of ways of selecting the route of 4 specific capitals is given by

$^{50}P_4= \frac{50!}{(50-4)!} = \frac{50!}{46!} =50\times49\times48\times47=5,527,200$

Therefore, the probability that she selects the route of four specific capitals is $\frac{1}{5,527,200}$

Part B:

The number of ways of selecting the route of 4 specific capitals is 5,527,200.

Since the number of ways of selecting the route of 4 specific capitals is too large it is not practical to list all of the different possible routes in order to select the one that is best.

Therefore, "No, it is not practical to list all of the different possible routes because the number of possible permutations is very large."

3 0

4 years ago

Solve for x. 5(x−3)= 3(x−2)

kirza4 [7]

Answer:

x = 9/2 or x= 4.5

Step-by-step explanation:

you factor out the equation:

5x-15=3x-6

+15 +15

5x=3x+9

-3x -3x

2x=9

x=9/2 or 4.5

3 0

3 years ago