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3 years ago

Two side of a triangle measure 7 and 9. Find the range of possible measures for the third side.

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

6 0

Answer:

anything greater than 2 and less than 16

Step-by-step explanation:

agasfer [191]3 years ago

5 0

Answer:

The Range of possible measures for the third side is; 2 < C < 16

Step-by-step explanation:

In a triangle with sides A , B and C , the sum of the length of any two sides of a triangle must be greater than the third side:

A+B>C
B+C>A
A+C>B

Given the two sides of a triangle are 7 and 9.

Let A = 7 and B = 9 then;

B-A< C < A+B

Then; the range of C can be:

9-7 < C < 7+9

Simplify:

2 < C < 16

Therefore, the range of possible measures for the third side is; 2 < C < 16

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Answer:

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3 years ago

Read 2 more answers

Find the value of x.

antoniya [11.8K]

Answer:

The value of x is 120°

Step-by-step explanation:

We should draw a line parallel to the given parallel lines and passes through the vertex of the measure x and divides it into two angles of measures x1 and x2, look at the attached figure

In the given figure

∵ The dashed line is parallel to the given line up

∴ The angle of the measure 70° and the angle x1 are alternate angles

∵ The alternate angles are equal in measures

∴ x1 = 70°

∵ The dashed line is parallel to the given line down

∴ The angle of the measure 50° and the angle x2 are alternate angles

∵ The alternate angles are equal in measures

∴ x2 = 50°

∵ x = x1 + x2

∴ x = 70 + 50

∴ x = 120°

∴ The value of x is 120°

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3 years ago

Read 2 more answers