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prohojiy [21]
3 years ago
11

Twice the difference of x and 5

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer:

2*(x-5) = -33, so x-5 = -16.5, so x = -11.5

This is assuming that "the difference between a and b" is a-b, which seems to be the accepted interpretation.

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Find the minimum and maximum of f(x,y,z)=x^2+y^2+z^2 subject to two constraints, x+2y+z=4 and x-y=8.
Alika [10]
The Lagrangian for this function and the given constraints is

L(x,y,z,\lambda_1,\lambda_2)=x^2+y^2+z^2+\lambda_1(x+2y+z-4)+\lambda_2(x-y-8)

which has partial derivatives (set equal to 0) satisfying

\begin{cases}L_x=2x+\lambda_1+\lambda_2=0\\L_y=2y+2\lambda_1-\lambda_2=0\\L_z=2z+\lambda_1=0\\L_{\lambda_1}=x+2y+z-4=0\\L_{\lambda_2}=x-y-8=0\end{cases}

This is a fairly standard linear system. Solving yields Lagrange multipliers of \lambda_1=-\dfrac{32}{11} and \lambda_2=-\dfrac{104}{11}, and at the same time we find only one critical point at (x,y,z)=\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right).

Check the Hessian for f(x,y,z), given by

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite, since \mathbf v^\top\mathbf{Hv}>0 for any vector \mathbf v=\begin{bmatrix}x&y&z\end{bmatrix}^\top, which means f(x,y,z)=x^2+y^2+z^2 attains a minimum value of \dfrac{480}{11} at \left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right). There is no maximum over the given constraints.
7 0
4 years ago
Find the sum 70.6+74.02+121.985=​
vova2212 [387]

266.605 is the answer.

Step-by-step explanation:

70.6 + 74.02 + 121.985 = 266.605

7 0
2 years ago
I'm running low on points can you please help me :) I will give brainiest promise
ioda

Answer: the ordered pair negative 3 over 8, negative 5 over 8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Joseph has 24 cousins he has 6 more females than males how many females does he have?
Brums [2.3K]
Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
6 0
3 years ago
Simplify: 3(r + 12r^2) – 2(r + 8)
Morgarella [4.7K]

Answer:

36r^2+r-16

Step-by-step explanation:

i did it

8 0
3 years ago
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