Answer:
C - 19 hours 27 minutes
Step-by-step explanation:
180 × 2 = 360
360 calories in an hour
3500 × 2 = 7000 (amount of calories in 2 pounds)
7000 ÷ 360 = 19.4444...
I hope this helps
Is this the whole equation?
Step-by-step explanation:
Cuz if not we need the whole question
At the end of the game you owned 13 cents if 71% of your rolls are successful and 29% of your rolls are unsuccessful option first is correct.
<h3>What is probability?</h3>
It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Every time you roll a 1 or 2 you are successful, and your friend will pay you $1. Every time you roll a 3, 4, 5 or 6, you must pay your friend $2.
71% of your rolls are successful:
= 1×0.71
= $0.71 (won)
29% of your rolls are unsuccessful
= 2×2.9
= $0.58 (lose)
The amount owned = 0.71 - 0.58 = $0.13 = 13 cents
Thus, at the end of the game you owned 13 cents if 71% of your rolls are successful and 29% of your rolls are unsuccessful option first is correct.
Learn more about the probability here:
brainly.com/question/11234923
#SPJ1
Answer:
√3 is irrational
Step-by-step explanation:
The location of the third point of a triangle can be found using a rotation matrix to transform the coordinates of the given points.
<h3 /><h3>Location of point C</h3>
With reference to the attached figure, the slope of line AC is √3, an irrational number. This means the line AC <em>never passes through a point with integer coordinates</em>. (Any point with integer coordinates would be on a line with rational slope.)
<h3>Equilateral triangle</h3>
The line segments making up an equilateral triangle are separated by an angle of 60°. If two vertices are on grid squares, the third must be a rotation of one of them about the other through an angle of 60°. The rotation matrix is irrational, so the rotated point must have irrational coordinates.
The math of it is this. For rotation of (x, y) counterclockwise 60° about the origin, the transformation matrix is ...
![\left[\begin{array}{cc}\cos(60^\circ)&\sin(60^\circ)\\-\sin(60^\circ)&\cos(60^\circ)\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}x'\\y'\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ccos%2860%5E%5Ccirc%29%26%5Csin%2860%5E%5Ccirc%29%5C%5C-%5Csin%2860%5E%5Ccirc%29%26%5Ccos%2860%5E%5Ccirc%29%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%27%5C%5Cy%27%5Cend%7Barray%7D%5Cright%5D)
Cos(60°) is rational, but sin(60°) is not. For any non-zero rational values of x and y, the sum ...
cos(60°)·x + sin(60°)·y
will be irrational.
As in the attached diagram, if one of the coordinates of the rotated point (B) is zero, then one of the coordinates of its image (C) will be rational. The other image point coordinate cannot be rational.