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3 years ago

A number is divided by 6, and then the quotient is added to 29. The result is 41.

Mathematics

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer:2

Step-by-step explanation:x/6+29=41

41-29=12

12/6=2

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Which expression equals a number that is NOT a rational number?

Leviafan [203]

Answer:

The correct answer would be 2π x 2²/5

Step-by-step explanation:

First, calculate the product, and evaluate the power which would be 2³π/5 and the solution is in an alternate form, therefore making it rational. :)

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2 years ago

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Stolb23 [73]

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3 years ago

A survey recently reported that the mean national annual expenditure for inpatient and outpatient services of all persons over 6

zlopas [31]

Using the z-distribution, it is found that the p-value for this test is of 0.0375.

At the null hypothesis, it is tested if the expenses are the same as the national average, that is, of $5,423. Hence:

$H_0: \mu = 5423$

At the alternative hypothesis, it is tested if it is higher, hence:

$H_1: \mu > 5423$

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 5516, \mu = 5423, \sigma = 979, n = 352$

The value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{5516 - 5423}{\frac{979}{\sqrt{352}}}$

$z = 1.78$

The p-value is the probability of finding a sample mean above $5,516, which is 1 subtracted by the p-value of z = 1.78.

Looking at the z-table, z = 1.78 has a p-value of 0.9625.

1 - 0.9625 = 0.0375

Hence, the p-value for this test is of 0.0375.

A similar problem is given at brainly.com/question/25549474

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2 years ago