Sounds true to me. But to make sure search it up on quizlet
Animalia, fungi , plantae , eubacteria,protista , archaebacteria
Answer:
A) One-half of their daughters will have normal color vision and brown eyes; 1/2 of their daughters will have normal color vision and blue eyes.
Explanation:
<u>The genotypes and phenotypes are</u>:
- BB or Bb= brown eyes
- bb= blue eyes
- XᴰXᴰ, XᴰXᵈ (women) or XᴰY (men)= normal vision
- XᵈXᵈ (women) or XᵈY (men) = color blind
A woman has blue eyes (bb) and normal color vision (she has an Xᴰ chromosome) but her father was color-blind, so the other X chromosome she has carries the recessive d allele. She has the genotype bb XᴰXᵈ.
The man has normal color vision (he is XᴰY) and has brown eyes, but his mother had blue eyes so he must have inherited a b allele from her and is therefore heterozygous Bb. His genotype is BbXᴰY.
The blue/brown eyes gene is autosomal and independent from the sex-linked color blindness gene.
The woman can produce the gametes b Xᴰ and b Xᵈ.
The man can produce the gametes B Xᴰ, b Xᴰ, B Y and bY.
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<u>The female daughters can have the following genotypes and phenotypes:</u>
- Bb XᴰXᴰ brown eyes, normal color vision
- Bb XᴰXᵈ brown eyes, normal color vision
- bb Xᴰ Xᴰ blue eyes, normal color vision
- bb Xᴰ Xᵈ blue eyes, normal color vision
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