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xxMikexx [17]
3 years ago
6

Chum salmon (Oncorhynchus keta) are born in freshwater environments and then migrate to the sea. Near the end of their lives, th

ey return to the freshwater stream where they were born to spawn. In fresh water, water constantly diffuses into the body and ions are lost from the body. In salt water, body water diffuses out of the body and excess ions are gained from the water. A salmon's gills have special cells to pump salt in or out of the body to maintain homeostasis. In response to the salmon's moves between fresh water and salt water, some cells in the gills are produced and others are destroyed. These changes made in the cells of the gills during the lifetime of an individual salmon are an example of which of the following?
A) evolution
B) trade-off
C) acclimatization
D) adaptation
E) luck
Biology
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

Acclimatization

Explanation:

Acclimatization is the change in the body of an organism in response to changes in the environment to maintain equilibrium (homeostasis). In the case of the salmon, when the environment changes from fresh to salt water and back, the chemical homeostasis would be altered if the fish didn't adjust. The adjustments in the fish gills are the response of the fish to acclimatize to the changes in the chemical environment in order to maintain homeostasis.

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Ainat [17]

Answer:

The correct answer is-

F1 -  AaBb (lacerate)

F2 - A_B_; A_bb; and aaB_ (lacerate)

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2. Two genes, with a dominant allele at either or both loci.

Explanation:

The given information gives THE following data:

Dominant: Lancerate leaves - AABB

Recessive: normal leaves - aabb

F1 has - all Lacerated leaves - AaBb

F2 by selfing F1:

         AB               Ab         aB         ab

AB    AABB        AABb      AaBB    AaBb

Ab     AABb       AAbb      AaBb     Aabb

aB     AaBB       AaBb       aaBB     aaBb

ab     AaBb       Aabb       aaBb      aabb

Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94

And normal 1/16 = 0.062 is almost same as 16/265 = 0.060

Thus, the genotypes of -

F1 -  AaBb (lacerate)

F2 - A_B_; A_bb; and aaB_ (lacerate)

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Answer:

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B. Stem Cells

Explanation:

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