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3 years ago

1.5=d+0.8 what’s the variable

Mathematics

1 answer:

andrezito [222]3 years ago

8 0

To solve, subtract .8 on both sides.
.7=d
Hope this helps!

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Hamid's normal weight is 80 kg.

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3 years ago

Tell whether the sequence 12, 4, -4, -12, -20, ... is arithmetic

Shkiper50 [21]

Answer:

yes, it is arithmetic as the common difference is -8

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3 years ago

Read 2 more answers

In a survey of 3000 people who owned a certain type of car, 2100 said they would buy that type of car again. What percent of th

Annette [7]

Answer:

Step-by-step explanation:

Step one:

given data

we are told that the number of people under the survey is 3000

and also that 2100 people would like to buy again, these 2100 people represent the number of people who are satisfied with the type of car.

Step two:

Therefore the percentage of this number related to the total people under the survey is given below

=2100/3000*100

=21//30*100

=7/10*100

=7*10

=70%

<u>Hence 70% of the people surveyed are satisfied with the type of car</u>

4 0

3 years ago

The number of students in a class is 60. The number of boys is seven-fifths the number of girls. Find the number of boys in the

Fynjy0 [20]

Step-by-step explanation:

Let the number of girls = x

Therefore, no. of boys = $\frac{7}{5} \times x$

$\because \: no \: of \: boys + no \: of \: girls \: = 60 \\ \\ \therefore \: \frac{7}{5} x + x = 60 \\ \\ \therefore \: \frac{7x + 5x}{5} = 60 \\ \\ \therefore \: \frac{12x}{5} = 60 \\ \\ \therefore \: x = 60 \times \frac{5}{12} \\ \\ \therefore \: x = 5 \times 5 \\ \\ \therefore \: x = 25 \\ \\ \therefore \: \frac{7}{5} x = \frac{7}{5} \times 25 = 7 \times 5 = 35 \\$

Thus, no of boys in the class is 35.

3 0

3 years ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 47.047.0 and

alisha [4.7K]

Answer:

0.025 = 2.5% probability that a given class period runs between 51.5 and 51.75 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is between c and d is given by the following formula

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

For this problem, we have that:

$a = 47, b = 57, c = 51.5, d = 51.75$ . So

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

$P(51.5 \leq X \leq 51.75) = \frac{51.75 - 51.5}{57 - 47} = 0.025$

0.025 = 2.5% probability that a given class period runs between 51.5 and 51.75 minutes.

4 0

3 years ago