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deff fn [24]
3 years ago
11

A jet fighter is capable of reaching speeds up to 1.5 x 10^3 miles per hour. A typical passenger plane can reach speeds of appro

ximately
5.0 x 10^2 miles per hour. About how many times faster can the jet fighter travel per hour than the typical passenger plane?
Mathematics
1 answer:
Volgvan3 years ago
5 0

Answer:

3 times faster

Step-by-step explanation:

\frac{1.5(10)^{3} }{5.0(10)^{2}} = \frac{1.5(10)}{5} = \frac{15}{5}  = 3 times faster

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Salsk061 [2.6K]
From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)

The answer is:
<span>D. Minimum at (2, 3)</span>
7 0
3 years ago
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IrinaVladis [17]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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X3 − 6x2 − 7x + 60 = 0
inna [77]
An equation ........
4 0
4 years ago
Bubbles bakery has 24 oatmeal cookies, 36 vanilla bean cookies, 42 chocolate chip cookies. What is the greatest common factor bu
STatiana [176]

Answer:6

Step-by-step explanation:

We have three groups of cookies as follows:

24   oatmeal

36   vanilla bean

42  chocolate chip

If we breack down into factors we get

24    2       24 = 2³ * 3        36    2   36 = 2²*3³         42   2   42 = 2*3*7

12     2                                 18    2                              21   3

6      2                                   9    3                                7   7

3      3                                   3    3                                1

1                                             1

Fom where we can get that biggest common factor is 6

24 ÷  6      =  4

36 ÷  6      =  6

42 ÷  6      =  7

Then Bakery will have  4 groups of oatmeal cookies, 6 of vanilla bean, and 7 chocolate chip

7 0
3 years ago
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vredina [299]

Answer:

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Step-by-step explanation:

Given two points on the line, we can find the slope using

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    = 1/3

3 0
3 years ago
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