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3 years ago

9

Dave has had a gym membership for 10 weeks. He goes to the gym 5 times a week. Each visit, he exercises for 1.75 hours. He spend

s 0.5 hours on the treadmill and the rest he spends on the stationary bicycle. How much time does Dave spend on the stationary bicycle in a week?

1 answer:

densk [106]3 years ago

8 0

75 x 5 = 375 hour in a week

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Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

4 years ago

The price of wheat in 1997 was 3.38 per bushel. In 1998,the price was 2.65 per bushel. Round the price per bushel of wheat for e

kifflom [539]

1997 = 3.40

1998 = 2.70

5 0

3 years ago

N/4=8/7 please show work

KatRina [158]

Answer:

n = 32/7

Step-by-step explanation:

n/4 = 8/7

Using cross products to solve

n*7 = 4*8

7n = 32

Divide each side by 7

7n/7 = 32/7

n = 32/7

5 0

3 years ago

Read 2 more answers

A phone company offers two packages of service. Package A is $50.00 per month with an additional charge of $0.20 per minute for

umka2103 [35]

Answer:

d

Step-by-step explanation:

mutipily

5 0

3 years ago

{-5 + y = -4<br> {4x - 4y = 16

Xelga [282]

Your answer should be (5, 1). But im not sure what your asking so I may be wrong.

8 0

3 years ago