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musickatia [10]
3 years ago
14

The hypotenuse of a right triangle is 50 millimeters long. One leg of the right triangle is 30 millimeters long. What is the len

gth of the other leg? (4 points)
Group of answer choices

20 millimeters

30 millimeters

40 millimeters

60 millimeters
Mathematics
2 answers:
Art [367]3 years ago
5 0

Answer:

the answer is 40 millimeters

iVinArrow [24]3 years ago
3 0

The answer is 40ml

I had this question :D

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olasank [31]

Answer:

1. 6 yd

2. 32 oz

3. 8 fl oz

4. 10560 ft

5. 2.5 ton

6.

Step-by-step explanation:

I can't see the rest of 6

4 0
3 years ago
Need help ASAP! Brainliest will be GRANTED to the right answer!
maksim [4K]
Length+height+width
5 0
3 years ago
What is the missing term?
spayn [35]
The answer is 2x^2 to the question
6 0
3 years ago
Read 2 more answers
A 12-foot ladder is placed against a wall with a 45-degree angle between the ladder and the ground. Using two different
Lelechka [254]

Answer:

24

Step-by-step explanation:

the wall meets the at a 45 degree angle and because of this we can draw a traingle allowing us to use the 45,45,90 method so then we do 12 times 2 and we get 24

7 0
2 years ago
The city of Madison regularly checks the quality of water at swimming beaches located on area lakes. Fifteen times the concentra
Maksim231197 [3]

Answer:

The sample standard deviation is 393.99

Step-by-step explanation:

The standard deviation of a sample can be calculated using the following formula:

s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }

Where:

s= Sample standart deviation

N= Number of observations in the sample

{\displaystyle \textstyle {\bar {x}}}= Mean value of the sample

and \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} } simbolizes the addition of the square of the difference between each observation and the mean value of the sample.

Let's start calculating the mean value:

\bar {x}=\frac{1}{N}  \sum_{i=1}^{N}x_{i}

\bar {x}=\frac{1}{15}*(180+1600+90+140+50+260+400+90+380+110+10+60+20+340+80)

\bar {x}=\frac{1}{15}*(3810)

\bar {x}=254

Now, let's calculate the summation:

\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=(180-254)^2+(1600-254)^2+(90-254)^2+...+(80-254)^2

\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=2173160

So, now we can calculate the standart deviation:

s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }

s=\sqrt[ ]{\frac{1}{15-1}*(2173160)}

s=\sqrt[ ]{\frac{2173160}{14}}

s=393.99

The sample standard deviation is 393.99

3 0
4 years ago
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