Answer:
Step-by-step explanation:
AR = QR = RS = (1/2) QS = 3
So ....by the Pythagorean Theorem, AS = AQ =
√ [3^2 + 3^2] = √[9 + 9 ] = √18
And the area of the two semi-circles= the area of a circle with a radius of AS/2 =
pi [AS/2]^2 =
pi [√18/2]^2 = 18pi/4 = (9/2)pi units^2
And the area of the rest of the figure is just that of a rhombus =
The product of the diagonals / 2 =
AB*QS/2 = 9 * 6 / 2 = 27 units^2
So....the total area =
[(9/2) pi + 27] units^2 = about = 41.1 units^2 [rounded]
Answer:
Step-by-step explanation:

Answer:
Step-by-step explanation:
On the real x-y plane, y = |x| is represented by two separate straight lines:
y = x for x >= 0, and
y = -x for x < 0
-3 to both sides
4b/2 = 8 +b
multiply both sides by two
(4b/2 = 8 + b) X2 = 4b = 16+2b
subtract 2b from both sides
2b = 16
divide both sides by 2
b=8
Answer:
no❤
Step-by-step explanation: