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eimsori [14]
3 years ago
6

Solve for x

c{x}{a} " align="absmiddle" class="latex-formula"> = \frac{y}{b}
Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0
X=a(y/b)
(just multiply a on both sides)
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Roberto wants to display his 18 sports cards in an album . Some pages hold 2 cards and others hold 3 cards .
nexus9112 [7]

Answer:

Step-by-step explanation:

Assuming Roberto wants to completely fill each page that he puts cards in, this function describes the number of 2-card pages, a, and 3-card pages, b.

2a + 3b =18

Ricardo can fill up 9 2-card pages, and 6 3-card pages.

a=9, b=0

We must add 2 3-card pages at a time,so that we have an even number for the 2-card pages:

a=6, b=2

Add 2 to b once more:

a=3, b=4

One more time:

a=0, b=6:

Thus, Ricardo can display his figures in the following page combinations:

a=9, b=0

a=6, b=2

a=3, b=4

a=0, b=6

Remember that a= number of 2-card pages and b=number of 3-card pages

There are 4 different ways that Ricardo can arrange his figures in terms of what kind of pages he uses. 

3 0
3 years ago
Identify a pattern and find the next number in the pattern.<br> -48, -24, -12, -6
vodka [1.7K]
It's would be plus haft that number (it's a negative) and the next number would be 0
3 0
3 years ago
Read 2 more answers
What is the degree? <br> f(x) = 1x5 + x2 +3.
Liono4ka [1.6K]

Answer:

3x^2 +3xh +h^2 -10 x- sh + 1, H=0

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What kind of function is being illustrated by f(x)=|2x³-3x|+5?
Dimas [21]

Answer:

Option D: Absolute value function

Step-by-step explanation:

The absolute value of a number is the distance of the number from 0 to the left or right on the number line.

We are given the function;

f(x) = |2x³ - 3x| + 5

This function contains an absolute value symbol which is |2x³ - 3x|.

This function is thus illustrated by an an absolute value function because an absolute value function will be one that contains algebraic expressions within absolute value symbols.

5 0
3 years ago
The probability density function of the time you arrive at a terminal (in minutes after 8:00 A.M.) is f(x) = 0.1 exp(−0.1x) for
Blababa [14]

f_X(x)=\begin{cases}0.1e^{-0.1x}&\text{for }x>0\\0&\text{otherwise}\end{cases}

a. 9:00 AM is the 60 minute mark:

f_X(60)=0.1e^{-0.1\cdot60}\approx0.000248

b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is

\displaystyle\int_{15}^{30}f_X(x)\,\mathrm dx\approx0.173

c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is

\displaystyle\int_0^{40}f_X(x)\,\mathrm dx\approx0.982

The probability of doing so for at least 2 of 5 days is

\displaystyle\sum_{n=2}^5\binom5n(0.982)^n(1-0.982)^{5-n}\approx1

i.e. you're virtually guaranteed to arrive within the first 40 minutes at least twice.

d. Integrate the PDF to obtain the CDF:

F_X(x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\begin{cases}0&\text{for }x

Then the desired probability is

F_X(30)-F_X(15)\approx0.950-0.777=0.173

7 0
3 years ago
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