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2 years ago

It says circle the numbers that are prime 21, 3, 18, 51, 2, 17, 6, 1, 91,

Mathematics

1 answer:

uysha [10]2 years ago

8 0

3 and 17 that’s all there is to it, prime numbers are numbers that don’t divide by anything but itself and one

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For the last 4.5 hours, the temperature has decreased at a rate of 2.8 Degrees Fahrenheit per hour. Which best represents the ov

faust18 [17]

Answer:

The overall change in temperature over the time period ∆T = -12.6°F

Step-by-step explanation:

Rate of change of temperature r = -2.8°F per hour

Time t = 4.5 hours

The overall change in temperature ∆T = Rate of change of temperature × time period

∆T = r × t

∆T = -2.8°F per hour × 4.5 hours

∆T = -12.6°F

The overall change in temperature over the time period is -12.6°F

Step-by-step explanation:

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3 years ago

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nirvana33 [79]

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2 years ago

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2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :