1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GuDViN [60]
3 years ago
10

A land surveyor can survey 1 3/5 miles of a land's borders in 1 1/4 hours. How long will it take him to complete a survey for 1

mile of a land's border?
Mathematics
1 answer:
MrRissso [65]3 years ago
8 0
This problem is an example of Ratio and Proportion.
We will write the problem into the form miles / hours = miles / hours

On the first survey of the surveyor, he took 1 3/5 miles for 1 1/4 hours.
Therefore, we can write this as 1 3/5 / 1 1/4 or 8/5 / 5/4

And on his second survey, it ask how long he will take for 1 mile.
So, we will let x for the number of hours he took the survey for 1 mile.
Therefore we can write this as 1 / x.

We will now equate the two surveys.
             \frac{ \frac{8}{5} }{ \frac{5}{4} } =  \frac{1}{x}
            \frac{8}{5} × \frac{4}{5} = 1 / x
                                             \frac{32}{25} =  \frac{1}{x}
we'll do cross multiplication, and it will become
                                             32x = 25
                                                 x = 25 / 32

Therefore, it will take him 25 / 32 hours to complete a survey for 1 mile.


                          
      

You might be interested in
Determine whether the lines are parallel, perpendicular, or neither. 5x + 2y = 14 and y = −5x + 9
valentinak56 [21]

Answer: Neither

Step-by-step explanation:

5x + 2y = 14

2y = -5x + 14

y = -5/2 x + 7; slope m = -5/2

y = –5x + 9 ; slope m = -5.

Parallel lines slopes are equal and perpendicular slopes are opposite and reciprocal.

So both lines are neither parallel nor perpendicular

Answer

C. Neither.

8 0
3 years ago
Plz solve if you can. Show ur work. I will name Brainliest! (: I need help plzzzzzzzzzz, especially on the check your work part.
maksim [4K]

1) -x + 4 = -2x - 6

Add(2x)

x+4=-6

Subtract(4)

x = -10

<u>Check your work</u>

-(-10)+4=-2(-10) - 6

10+4=-2(-10) - 6

14=-2(-10)

14=20 - 6

14=14

Correct :)

2) 4R - 4 = 3R + 10

Add 4

4R=3R+14

Subtract 3R

R = 14

<u>Check your work</u>

4(14)-4=3(14)+10

56-4=3(14)+10

52=3(14)+10

52=42+10

52=52

Correct :)

3) 2Y - 3 = Y - 4

Add 3

2Y = Y - 1

Subtract Y

Y = -1

<u>Check your work</u>

2(-1)-3=-1-4

-2-3=-1-4

-5=-5

Correct :)

<em>Hope it helps <3</em>

6 0
3 years ago
Find AD. Show how you got your answer.
stealth61 [152]
Notice the picture below
the AD line is a bisector, cutting the 36 degrees A in half,
18 and 18 degrees each half

notice the tickmarks, the triangle is an isosceles,
if those two sides are equal, so are the angles they make
down below with the base

now, the base is 8, AD is bisecting that too, to 4 and 4

now, using the Law of Sines

\bf \textit{Law of sines}&#10;\\ \quad \\&#10;\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\&#10;----------------------------\\\\&#10;\cfrac{sin(18^o)}{4}=\cfrac{sin(72^o)}{\overline{AD}}\implies \overline{AD}=\cfrac{4\cdot sin(72^o)}{sin(18^o)}

keep in mind, the angles are in degrees, so, when taking the sines, make sure your calculator is in Degree mode

4 0
3 years ago
100 points + brainiest
Scrat [10]

Answer:

  • 35 grams of 11.43% solution

Step-by-step explanation:

The end solution has same volume as initial volumes of mixture.

  • 10 + 25 = 35 g

The concentration of solution is calculated as below

  • 10*0.15 + 25*0.1 = 4 g
  • 4 / 35*100% = 11.43% (rounded)

6 0
2 years ago
Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
SpyIntel [72]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad &#10;\begin{array}{llll}&#10;g(x)=&\sqrt{0.5x}\\&#10;&\quad \uparrow \\&#10;&\quad  B&#10;\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
8 0
3 years ago
Read 2 more answers
Other questions:
  • Can someone one please give me the answer!!
    12·1 answer
  • 1. 3+(-8)=
    8·1 answer
  • 5. (0,0) and (-2,-8) Slope=_ Equation=​
    9·1 answer
  • A researcher designs an experiment by manipulating the following variables: temperature (low or high), illumination level (low o
    11·1 answer
  • Complete the square to find the y-value for the minimum value of the function-f(x)=x^2-8x+28
    7·1 answer
  • I need help im not ready for avid
    5·1 answer
  • Determine the height in meters of a triangle with an area of 72 square meters and a base of 28 meters.​
    10·1 answer
  • Solve number 11 pls
    7·1 answer
  • What is the tangent<br> ratio of angle C₂ ?
    8·1 answer
  • Write the quantity as percentage of the second (give answers to the nearest whole number).
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!