I need to show work help meee

$\Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})$

where the symbol $\Phi$ (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, $\mu$ is the mean and $\sigma$ is the standard deviation of the normal distribution defined as $N(\mu, \ \sigma)$ .

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution $N(113, \ 12)$ ,

$\Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973$

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0

2 years ago

When I get multiplied by any number, the sum of the figures in the product is always me. What am I?

vladimir1956 [14]

Answer: 9

Step-by-step explanation:

When you multiply 9*9, you get 81 whose sum is 9 (8+1)

Likewise, 9*8=72( 7+2=9)

8 0

3 years ago

Read 2 more answers

The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 3 se

aniked [119]

52 - 38 is 14
since on the second they sold one more child ticket then the first day we know the extra money is the price of a child ticket
so 14 is how much a child ticket is
if 3 senior citizen tickets but 14$ = 38
subtract 14 from38 = 24
and then 24/3 =senior ticket
child:14$
senior:8$

5 0

3 years ago