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elixir [45]
3 years ago
9

⭐️GIVING BRAINLIEST⭐️

Mathematics
1 answer:
lozanna [386]3 years ago
4 0
They pay $16,290 in taxes and deductions, so $108,600 divided by $16,290 is around 6.6%
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P= 3⁷ × 11² and Q= 3⁴ × 7³× 11 The HCF of P and Q​
Volgvan

Answer:

3⁷ x 7³ x 11²

Just write down the product of the highest power of all the powers that appear in either or both numbers.

8 0
2 years ago
38. A baseball park's average game attendance is 2035 people. This is 65
marta [7]

Answer:

<u><em>1970</em></u> is the answer for the question "A baseball park's average game attendance is 2035 people. This is 65 more than the average attendance for last year. What was the average game attendance for last year?"

<u><em>- hope this helps!:)</em></u>

6 0
2 years ago
Help picture below problem 8
Radda [10]

Answer:

C. never

Step-by-step explanation:

A trapezoid has exactly one pair of opposite sides parallel.

A parallelogram has exactly two pairs of opposite sides parallel.

A trapezoid is never a parallelogram.

6 0
2 years ago
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
X+12/2x-5 - 3x-2/2x-5
BARSIC [14]

Answer:

the answer to this question is 3x-10

8 0
3 years ago
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