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gladu [14]
3 years ago
9

If h(r) = 23r − 6, what is the value of h(-9)? Question 5 options: a) 0 b) 12 c) −623 d) -12

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0

Answer:

-213

Step-by-step explanation:

If h(r) = 23r − 6, then, if we choose r = 2 as an example (only), then:

If h(2) = 23(2) − 6 = 46 - 6 = 40

Using the same approach, we substitute -9 for r, obtaining:

If h(-9) = 23(-9) − 6 = -207 - 6 = -213

This does not match any of the given possible answers.  Please ensure that you have copied down the problem and possible answers accurately.

In-s [12.5K]3 years ago
6 0

Answer:

-213

not in d option though check d question

Step-by-step explanation:

h(r) = 23r − 6

h(-9) = 23(-9) - 6

= -207 - 6

= -213

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40.32 is 76.8% of what number?
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An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had
Stolb23 [73]

Answer:

Q1 z(s) is in the rejection region for H₀ ; we reject H₀. We can´t support the that means have no difference

Q2  CI 95 %  =  (  0,056 ;  0,164 )

Step-by-step explanation:

Sample information for people under 18

n₁  =  500

x₁ =  180

p₁  =  180/ 500    p₁  =  0,36    then  q₁  =  1 -  p₁     q₁ =  0,64

Sample information for people over 18

n₂  =  600

x₂  =  150

p₂  =  150 / 600   p₂ =  0,25   then   q₂  =  1 - p₂   q₂ =  1 - 0,25   q₂ = 0,75

Hypothesis Test

Null hypothesis                        H₀              p₁  =  p₂

Alternative Hypothesis           Hₐ              p₁  ≠  p₂

The alternative hypothesis indicates that the test is a two-tail test.

We will use the approximation to normal distribution of the binomial distribution according to the sizes of both samples.

Testin at CI =  95 %    significance level is  α = 5 %   α  =  0,05  and

α/ 2  =  0,025   z (c) for that α  is from z-table:

z(c) = 1,96

To calculate   z(s)

z(s)  =  ( p₁  -   p₂ ) / EED

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EED = √( 0,36*0.64)/500  +  (0,25*0,75)/600

EED = √0,00046  +  0,0003125

EED = 0,028

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Then

z(s)  =  0,11 / 0,028

z(s) = 3,93

Comparing  z(s) and  z (c)    z(s) > z(c)

z(s) is in the rejection region for H₀ ; we reject H₀. We can´t support the idea of equals means

Q2  CI  95 %   =  (  p₁  -  p₂  ) ±  z(c) * EED

CI 95%  =  ( 0,11   ±  1,96 * 0,028 )

CI 95%  = (  0,11  ±  0,054 )

CI 95 %  =  (  0,056 ;  0,164 )

8 0
2 years ago
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