Answer:
<h2>D.4/12</h2>
Step-by-step explanation:
<h3>I took the test to</h3>
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Answer is b . G)f(x))=9x^3+30x
Hey there! I'm happy to help!
Let's call the hamburgers h and the cheeseburgers c.
h+c=500
c=h-50
Let's plug this value for c into the first equation to solve for h.
h+h-50=500
2h-50=500
Add 50 to both sides.
2h=550
Divide both sides by 2.
h=275
Therefore, 275 hamburgers were sold on Wednesday.
Have a wonderful day! :D
Answer:
y = 2/3x - 3
Step-by-step explanation:
Step 1: Write equation
2x - 3y = 9
Step 2: Solve for <em>y</em>
- Subtract 2x on both sides: -3y = 9 - 2x
- Divide both sides by -3: y = -3 + 2/3x
- Rewrite: y = 2/3x - 3