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Eddi Din [679]
3 years ago
7

Determine whether the statement is true or false. If f and g are positive increasing functions on an interval I, then fg is incr

easing on I. a. True b. False
Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer: false

Step-by-step explanation:

If f and g are increasing on I, this implies that f' > 0 on I and g' > 0 on I. That is both f' and g' have a positive slope. However,

Using product rule;

(fg)' = fd(g) + gd(f)

(fg)' = f * g' + f' * g

and although it is given that g' and f' are both positive we don't have any information about the sign of the values of the functions themselves(f and g). Therefore, if at least one of the functions has negative values there is the possibility that the derivative of the product will be negative. For example;

f = x, g = 5x on I = (-5, -2)

f' = 1 and g' =5 both greater than 0

f and g are both lines with positive slopes therefore they are increasing, but f * g = 5x^2 is decreasing on I.

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2x + 19 and x + 23 are alternate exterior angles. What is the value of x? *
Mamont248 [21]

Answer:

4

Step-by-step explanation:

2x+19=x+23

We simplify the equation to the form, which is simple to understand

2x+19=x+23

We move all terms containing x to the left and all other terms to the right.

+2x-1x=+23-19

We simplify the left and right sides of the equation.

+1x=+4

We divide both sides of the equation by 1 to get x.

x=4

5 0
3 years ago
Find the zero of the function:<br> y= 11x^2+25x-24
Ann [662]
X=8/11,-3 is the answer to your question.
4 0
3 years ago
Which function represents g(x), a reflection of f(x) = 6(one-third) Superscript x across the y-axis?
Rasek [7]

The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection across the axes

  • If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
  • If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)

∵ f(x)=6(\frac{1}{3})^{x}

∵ g(x) is the image of f(x) after reflection across the y-axis

- From the rule above reflection across the y-axis changes the sign of x

∴ g(x)=6(\frac{1}{3})^{-x}

∵ (a)^{-n}=(\frac{1}{a})^{n}

∵ (\frac{1}{a})^{-n}=(a)^{n}

∴ (\frac{1}{3})^{-x}=(3)^{x}

∴ g(x)=6(3)^{x}

The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
An amphitheater was 19 seats in the front row, 22 in the second, 25 in the third, and so on, for 24 rows
Scorpion4ik [409]

Answer:

Answer: 572

Step-by-step explanation:

5 0
3 years ago
What is an equation of the parabola with vertex at the origin and focus (0, 0.75)?
morpeh [17]

Answer:

x^{2} =3y

Step-by-step explanation:

Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form

x^{2} =4py

Because the parameter p is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.

Replacing the parameter value, we have

x^{2} =4(0.75)y\\x^{2} =3y

Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is x^{2} =3y.

8 0
3 years ago
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