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Dima020 [189]
3 years ago
15

steven and jaden are solving b is either of them correct? explain your reasoning and in complete sentences.

Mathematics
1 answer:
sveta [45]3 years ago
4 0

Answer:

17

Step-by-step explanation:

You just add them

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A triangle has sides with lengths of 7 feet, 15 feet, and 17 feet. is it a right triangle?
aksik [14]
To test if this is a right triangle, let's test these side lengths with the Pythagorean Theorem.

a^2 + b^2 = c^2

c is the hypotenuse, the longest side of a right triangle.
a and b are the legs of the right triangle.

a = 7
b = 15
c = 17

7^2 + 15^2 = 17^2 ?

49 + 225 = 289 ?

274 ≠ 289

Thus, this triangle is not a right triangle since it does not satisfy the Pythagorean Theorem.

Have an awesome day! :)
8 0
3 years ago
G=4ca-3ba, find a <br>Also plz show how u found the answer.
lina2011 [118]
G=4ca-3ba <=> G=a(4c-3b)

                   <=> a=G/(4c-3b)
8 0
3 years ago
Read 2 more answers
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
Find the common ratio and an explicit form in each of the following geometric sequences.
Margaret [11]

Answer:

The explicit form is a_{n}=162(2/3)^{n-1}

Step-by-step explanation:

The explicit form of a geometric sequence is given by:

a_{n}=ar^{n-1}

where an is the nth term, a is the first term of the sequence and r is the common ratio.

In this case:

a=162

The value of the common ratio is obtained by dividing one term by the previous term.

For the first and second terms:

108/162=2/3

For the second and third terms (In order to prove that 2/3 is the common ratio)

72/108=2/3

Therefore:

r=2/3

Replacing a and r in the formula:

a_{n}=162(2/3)^{n-1}

7 0
3 years ago
4 - 2(x-4)/ 3= 3(2x+5)/2<br>pls answer fast​
adell [148]

Answer:

-21/22

Step-by-step explanation:

1.Apply fraction cross multiply

2. Simplify

3.Expand

4.Subtract 24 from both sides

5.simplify

6. Subtract 18x form both sides

7.Simpiify, then divide both sides by -22to get answer.

7 0
3 years ago
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