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Oksi-84 [34.3K]
3 years ago
14

Based on a​ survey, assume that 32​% of consumers are comfortable having drones deliver their purchases. Suppose that we want to

find the probability that when six consumers are randomly​ selected, exactly three of them are comfortable with delivery by drones. Identify the values of​ n, x,​ p, and q.
Mathematics
1 answer:
Nikolay [14]3 years ago
3 0

Answer:

n = 6

x = 3

p = 0.32

q = 0.68

Step-by-step explanation:

Given:

32% are comfortable having drones deliver their purchases.

Suppose we are to find the probability that when 6 consumers are randomly​ selected, exactly 3 of them are comfortable with delivery by drones.

Required:

Find n, x, p, and q.

i) n represents the sample size. Here 6 consumers are selected randomly, therefore the sample size here is 6.

Thus, n = 6

ii) x represents the sample mean or number of successes. Since 3 consumers out of the selected 6 are comfortable with delivery by drones, the sample mean here is 3.

Thus, x = 3

iii) p represents population proportion or probability of success. Here population proportion(success probability) is 32% ≈ 0.32.

Thus, p = 0.32

iv) q represents probability of failure. To find probability of failure, use the formula:

1 - p

Thus,

1 - 0.32 = 0.68

q = 0.68

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Evaluate the line integral, where c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
Arada [10]

The value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)

x(t) = (1-t)0 + t×2 = 2t  

y(t) = (1-t)0 + t×3 = 3t

z(t) = (1-t)0 + t×4 = 4t

Finding its derivative;

x'(t) = 2

y'(t) = 3

z'(t) = 4

The line integral is given by:

\rm \int\limits_C {xe^{yz}} \, ds = \int\limits^1_0 {2te^{12t^2}} \, \sqrt{2^2+3^2+4^2} dt

 

\rm ds = \sqrt{2^2+3^2+4^2} dt

After solving the integration over the limit 0 to 1, we will get;

\rm \int\limits_C {xe^{yz}} \, ds = \dfrac{\sqrt{29}}{12}  (e^{12}-1)   or

= 73037.99 ≈ 73038

Thus, the value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

Learn more about integration here:

brainly.com/question/18125359

#SPJ4

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2 years ago
Write the equation in standard form for the circle that has a diameter with endpoints (22,0) and (2,0)
vovikov84 [41]

Answer:

(x - 12)² + y² = 100

Step-by-step explanation:

The standard form of the equation of a circle is;

(x - a)² + (y - b)² = r²

where:

a and b are the coordinates of the centre of the circle

r is the radius

We are given the coordinates of the endpoints of the diameter as; (22,0) and (2,0)

Thus, the centre of the circle would be at the mid point of the endpoints of the diameter.

Coordinates of the centre is;

((22 + 2)/2), (0 +0)/2))

This is;

(12, 0)

So, a = 12 and b = 0

Now,to get the radius r, we will use the formula;

r = √[(x2 - x1)² + (y2 - y1)²]

Where;

(x1, y1) and (x2, y2) are 2 points namely (12,0) and (22, 0)

r = √[(12 - 22)² + (0 - 0)²]

r = √(-10)²

r = √100

r = 10

Thus,equation of the circle is;

(x - 12)² + (y - 0)² = 10²

(x - 12)² + y² = 100

7 0
3 years ago
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