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3 years ago

6

How do I determine the 50th term for the sequence -5, -1, 3, 7, 11

1 answer:

Aneli [31]3 years ago

3 0

The sequence is going up by 4 so u have to multiply each term by four and the -5 is it’s 0th term as well it’s beginning so you have to input that in the equation as well
4(50) - 5 = 200 - 5 = 195
I’m not very good at explaining so I hope u get it

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3 years ago

How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!

larisa [96]

$\huge \bf༆ Answer ༄$

Let's solve this using unitary method ~

$\sf3 \: seconds = 63 \: meters$

$\sf1\: second= 63 \div 3 \: meters$

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3 years ago

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fgiga [73]

Answer:

$|z| = 27$ -- Modulus

$\theta = \frac{\pi}{3}$ --- Argument

Step-by-step explanation:

Given

$((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Required

Determine the modulus and the argument

We have that:

$z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Expand:

$z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

A complex equation can be expressed as:

$z = |z| e^{i\theta}$

Where

$|z| = modulus$

$\theta = argument$

Where

$e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})$

So:

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$ becomes

$z = 27(e^{i\frac{\pi}{18}})^6$

By comparison:

$e^{i\theta} = (e^{i\frac{\pi}{18}})^6$

This gives:

${i\theta} = i\frac{\pi}{18}}*6$

${i\theta} = i\frac{6\pi}{18}}$

${i\theta} = i\frac{\pi}{3}}$

Divide through by i

$\theta = \frac{\pi}{3}$

Hence, the modulus, z is:

$|z| = 27$

And the argument $\theta$ is

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3 years ago

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lubasha [3.4K]

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Svet_ta [14]

Answer:

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