Most of the energy we use originally came from:

Given half a chance other people at work will take advantage of you

Damm [24]

have self-control and if you have a problem dont be afraid to speak your mind, show other people you mean buisness, but be polite to aviod starting more problems

3 0

3 years ago

Write a function `has_more_zs` to determine which of two strings contains # more instances of the letter "z". It should take as

nekit [7.7K]

Answer:

// Method's name: has_more_zs

// Parameters are text1 and text2 to hold the two phrases to be tested

public static String has_more_zs(String text1, String text2) {

// Create and initialize z1 to zero

// Use z1 to count the number of zs in text1

int z1 = 0;

// Create and initialize z2 to zero

// Use z2 to count the number of zs in text2

int z2 = 0;

//Create a loop to cycle through the characters in text1

//Increment z1 by one if the current character is a 'z'

int i = 0;

while (i < text1.length()) {

if (text1.charAt(i) == 'z' || text1.charAt(i) == 'Z') {

z1 += 1;

}

i++;

}

//Create a loop to cycle through the characters in text2

//Increment z2 by one if the current character is a 'z'

i = 0; //Re-initialize i to zero

while (i < text2.length()) {

if (text2.charAt(i) == 'z' || text2.charAt(i) == 'Z') {

z2 += 1;

}

i++;

}

//Using the values of z1 and z2, return the necessary statements

if (z1 > z2) {

return "The phrase '" + text1 + "'" + " has more occurences of z than the phrase " + "'" + text2 + "'";

}

else if (z1 < z1) {

return "The phrase '" + text2 + "'" + " has more occurences of z than the phrase " + "'" + text1 + "'";

}

else if (z1 == z2) {

return "The strings have the same number of z";

}

else {

return "Neither string contains the the letter z";

}

Explanation:

Explanation to answer has been given in the code as comments. Please refer to the comments for the details of the code.

The source code file has been attached to this response and saved as "NumberOfZs.java"

Hope this helps!

Download java

5 0

3 years ago

Primary storage is electronic storage connected directly to the CPU. true or false

Helen [10]

Answer:

I think it's true

Explanation:

I don't know but If I'm wrong tell me?

7 0

2 years ago

You write a short story, but you want to make sure your work is protected before you post it online. What should you do to help

Mars2501 [29]

Make sure you but no copyright, author, and date of publication, that may help.

8 0

3 years ago

A palindrome is a string that reads the same from left to right and from right to left. Design an algorithm to find the minimum

stepladder [879]

Answer:

Explanation:

The following code is written in Python. It is a recursive function that tests the first and last character of the word and keeps checking to see if each change would create the palindrome. Finally, printing out the minimum number needed to create the palindrome.

import sys

def numOfSwitches(word, start, end):

if (start > end):

return sys.maxsize

if (start == end):

return 0

if (start == end - 1):

if (word[start] == word[end]):

return 0

else:

return 1

if (word[start] == word[end]):

return numOfSwitches(word, start + 1, end - 1)

else:

return (min(numOfSwitches(word, start, end - 1),

numOfSwitches(word, start + 1, end)) + 1)

word = input("Enter a Word: ")

start = 0

end = len(word)-1

print("Number of switches required for palindrome: " + str(numOfSwitches(word, start, end)))

3 0

2 years ago