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daser333 [38]
3 years ago
14

Plz help me im stuck

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Answer:

x = 50 ounces

Step-by-step explanation:

call the capacity of bottle x ounce

Anna has a water bottle that is half full. -> x/2

After she drinks 15 fluid ounces from the bottle, it is only one-fifth full

-> (x/2)-15 = x/5

-> 3x/10 = 15

-> x = 50 ounces

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Write an equation to represent the following statement.<br> The sum of j and 47 is 55<br> .
scZoUnD [109]

Answer:

j + 47 = 53

Step-by-step explanation:

3 0
3 years ago
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Sanji scored 125 points in the first round of a video game and 263 points in the second round. His total score after the third r
GaryK [48]
Sanji scored 44 points more in the third round than in the first round.
4 0
2 years ago
PLEASE PLEASE HELP ​
nekit [7.7K]

Answer:68.3 degrees

Step-by-step explanation:

The diagram of the triangle ABC is shown in the attached photo. We would determine the length of side AB. It is equal to a. We would apply the cosine rule which is expressed as follows

c^2 = a^2 + b^2 - 2abCos C

Looking at the triangle,

b = 75 miles

a = 80 miles.

Angle ACB = 180 - 42 = 138 degrees. Therefore

c^2 = 80^2 + 75^2 - 2 × 80 × 75Cos 138

c^2 = 6400 + 5625 - 12000Cos 138

c^2 = 6400 + 5625 - 12000 × -0.7431

c^2 = 12025 + 8917.2

c = √20942.2 = 144.7

To determine A, we will apply sine rule

a/SinA = b/SinB = c/SinC. Therefore,

80/SinA = 144.7/Sin 138

80Sin 138 = 144.7 SinA

SinA = 53.528/144.7 = 0.3699

A = 21.7 degrees

Therefore, theta = 90 - 21.7

= 68.3 degees

8 0
3 years ago
A bag of chocolates is labeled to contain 0.384 pounds of chocolates. The actual weight of the chocolates is 0.3798 pounds. Are
Marta_Voda [28]

Based on the information given the chocolates stated on the label is 0.0042-ounce lighter.

Weight:

Using this formula

Chocolate weight=Current weight-Actual weight

Where:

Current weight=0.384

Actual weight=0.3798

Let plug in the formula

Chocolate weight=0.384-0.3798

Chocolate weight=0.0042 ounce

In conclusion, the chocolates stated on the label are 0.0042-ounce lighter.

6 0
2 years ago
Of the 100 entries in a costume contest, 39 entrants were dressed as heroes and 45 entrants were wearing a mask. If 21 entrants
ehidna [41]

Correct question with correct options has been attached

Answer:

37

Step-by-step explanation:

Let C represent those dressed as heroes and let B represent those wearing mask

Thus;

n(C) = 39

n(D) = 45

We are told that 21 entrants were dressed as heroes wearing a mask.

Thus; n(C n D) = 21

We are also told that there were a total of 100 entries.

Thus, n(T) = 100

Now, number of entrants neither dressed as heroes nor wearing a mask is given by;

n(T) - n(C u D)

n(C u D) = n(C) + n(D) - n(C n D)

n(C u D) = 39 + 45 - 21

n(C u D) = 63

Thus;number of entrants neither dressed as heroes nor wearing a mask is: 100 - 63 = 37

3 0
3 years ago
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