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2 years ago

Which transformation can you use to show that these shapes are congruent?

Mathematics

1 answer:

Zarrin [17]2 years ago

4 0

Answer:

Rotations, reflections, and translations are isometric. That means that these transformations do not change the size of the figure. If the size and shape of the figure is not changed, then the figures are congruent.

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What is the value of a in this function's equation? A. -1 B. 1 C. 2 D. -2

Pavlova-9 [17]

B is the correct answer !!!!

7 0

2 years ago

If you can answer any of these that would be great !

Andrej [43]

Answer:

Step-by-step explanation:

number 2) 0

4 0

2 years ago

Read 2 more answers

9. The figure shows a rectangle with its length and

lora16 [44]

Answer:

875cm^2

Step-by-step explanation:

since opposite sides are equal

3x-y=2x+y

x=2y

y=x/2 ....(i)

thus new length=2x+y

=2x+(x/2) [using (i)]

=(4x+x)/2

l=5x/2 .....(ii)

now,

perimeter=2(l+b)=120cm

l+b=60cm

from figure and using (ii)

[5x/2]+2x-3=60

[5x+4x-6]/2=60

9x-6=120

9x=126

x=126/9

x=14 ..........(iii)

substitute (iii) in (i)

y=14/2

y=7 ...........(iv)

From figure,

length=2x+y [using (iii) and (iv)]

=2x14+7

length=35cm

breadth=2x-3

=2x14-3 ....[using(iii)]

=28-3

breadth=25cm

now,

Area=lxb

=35x25

=875cm^2

7 0

3 years ago

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

 $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago

For each example, select the type of transformation shown. Then write if the figures are similar or congruent in the space provi

Pavel [41]

Answer:

i got them right

Step-by-step explanation:

A is translated and congruent

B is dilated and similar

C is reflected and congruent

depending on how your quiz is when is say and then a word like "congruent" that word is the one you type in and the other word translated,dilated and reflected is from the drop down bar. any questions on how this is set up

6 0

2 years ago