5 times amount of people has to be bigger than 2112

5(133+v)≥2112
distribute
665+5v≥2112
minus 665 from both sides
5v≥1447
divide both sides by 5
v≥289.4
yo can't have 0.4 volunterer
v≥290

has to have at least 290 volunteers

8 0

2 years ago

Solve for w. 5w + 9z = 2z + 3w w = z w = z w = –2z w = –7z

Semenov [28]

5w + 9z = 2z + 3w

Move terms with w to the left - subtract 3w from both sides

2w + 9z = 2z

Subtract 9z from both sides

2w = -7z

Divide both sides by 2

w = $\frac{-7}{2}z$

6 0

2 years ago

One-half of a number, increased by 69 is 74. What is the number?

Klio2033 [76]

Answer:

Step-by-step explanation:

let the number be n then half the number is $\frac{1}{2}$ n , so

$\frac{1}{2}$ n + 69 = 74 ( subtract 69 from both sides )

$\frac{1}{2}$ n = 5 ( multiply both sides by 2 to clear the fraction )

n = 10

Thus the number is 10

6 0

2 years ago

Read 2 more answers

Somebody please help so I can pass, please

ASHA 777 [7]

First, we are going to find the vertex of our quadratic. Remember that to find the vertex $(h,k)$ of a quadratic equation of the form $y=a x^{2} +bx+c$ , we use the vertex formula $h= \frac{-b}{2a}$ , and then, we evaluate our equation at $h$ to find $k$ .

We now from our quadratic that $a=2$ and $b=-32$ , so lets use our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-32)}{2(2)}$
$h= \frac{32}{4}$
$h=8$
Now we can evaluate our quadratic at 8 to find $k$ :
$k=2(8)^2-32(8)+56$
$k=2(64)-256+56$
$k=128-200$
$k=-72$
So the vertex of our function is (8,-72)

Next, we are going to use the vertex to rewrite our quadratic equation:
$y=a(x-h)^2+k$
$y=2(x-8)^2+(-72)$
$y=2(x-8)^2-72$
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.

We can conclude that:
The rewritten equation is $y=2(x-8)^2-72$
The x-coordinate of the minimum is 8

8 0

3 years ago

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