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Eduardwww [97]
3 years ago
10

In how many ways can 13 people be divided into four groups with 3, 6, 2 and 2 people respectively?

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

Total combination = 180,180

Step-by-step explanation:

It is a combination based problem.

So,

Total people = 13

Group = 3,6,2,2

So,

For 6 people

13C6= 1,716

For 3 people

7C3 = 35

For 2 group of 2 people

(4C2)/2 = 3

Total combination = 1,716 × 35 × 3

Total combination = 180,180

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Step-by-step explanation:

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=> \frac{(-3 \times 3) - 11}{21}

=> \frac{-9 - 11}{21}

=> \frac{-20}{21}

  • Find the additive inverse of  \frac{-20}{21} by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of  \frac{-20}{21}.

=> x + \frac{-20}{21} = 0

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=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }

=> \frac{9}{5} \times \frac{5}{7}

=> \frac{9}{7}

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=> \frac{9}{7} \times \frac{20}{21}

=> \frac{180}{147}

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