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Eduardwww [97]
3 years ago
10

In how many ways can 13 people be divided into four groups with 3, 6, 2 and 2 people respectively?

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

Total combination = 180,180

Step-by-step explanation:

It is a combination based problem.

So,

Total people = 13

Group = 3,6,2,2

So,

For 6 people

13C6= 1,716

For 3 people

7C3 = 35

For 2 group of 2 people

(4C2)/2 = 3

Total combination = 1,716 × 35 × 3

Total combination = 180,180

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$500 - $200 = $300 dollars left.

$300 divided by $10 = 30 weeks.

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3 years ago
12-(-4)(-3), evaluate please
Sindrei [870]

Answer:

0

Step-by-step explanation:

12-(-4)(-3)

-3 x -4 = 12

12 - 12= 0

5 0
3 years ago
Read 2 more answers
A survey was given to 339 people asking whether people like dogs and/or cats.
lina2011 [118]

Answer:

80

Step-by-step explanation:

Think of it as a Venn diagram.  One circle is the people who like dogs, and one circle is the people who like cats.  The overlap is people who like both dogs and cats.

190 people in the survey said they like dogs.  That includes the people who like both dogs and cats.

141 people in the survey said they like cats.  That includes the people who like both dogs and cats.

If we simply add the two numbers together, we'll be counting the overlap twice.  So to find the total number of people who like dogs or cats, we have to subtract one overlap.

dogs or cats = 190 + 141 − x

Therefore:

190 + 141 − x + 88 = 339

419 − x = 339

x = 80

80 people said they liked both cats and dogs.

5 0
3 years ago
Segment MN has endpoints at M(-5, 4) and N(7, -5). What is the midpoint of MN???? PLZ HELP
Paha777 [63]
Theres a formula to find the midpoint it’s... (x1+x2)/2, (y1+y2)/2. You fill in the x’s and y’s to get (-5+7)/2 for x, which equals 1 and (4-5)/2 to get -0.5. (1, -0.5) is your answer

7 0
3 years ago
Consider the following scenario: Let P(C) = 0.4. Let P(D) = 0.5. Let P(C|D) = 0.6. a. Find P(C AND D). b. Are C and D mutually e
Nataly_w [17]

a. By definition of conditional probability,

P(C | D) = P(C and D) / P(D)  ==>  P(C and D) = 0.3

b. C and D are mutually exclusive if P(C and D) = 0, but this is clearly not the case, so no.

c. C and D are independent if P(C and D) = P(C) P(D). But P(C) P(D) = 0.2 ≠ 0.3, so no.

d. Using the inclusion/exclusion principle, we have

P(C or D) = P(C) + P(D) - P(C and D)  ==>  P(C or D) = 0.6

e. Using the definition of conditional probability again, we have

P(D | C) = P(C and D) / P(C)  ==>  P(D | C) = 0.75

3 0
3 years ago
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