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2 years ago

Polygon Angle Sums - Part 2

Mathematics

1 answer:

Rashid [163]2 years ago

5 0

Answer:

x = 80°

Step-by-step explanation:

Find attached the complete question with diagram. Also find attached the diagram used for solving the question.

There area 3 angles in the diagram:

x + 8, 2x + 12, x + 20

Let the interior angles be labelled a, b, and c

a+ 2x+12 = 180° (sum of angles on a straight line)

a= 180-(2x+12) = 168 -2x in degrees

b+ x+20 = 180° (sum of angles on a straight line)

b = 180-(x+20) = 160 -x in degrees

c+ x+8 = 180° (sum of angles on a straight line)

c = 180-(x+8) = 172-x in degrees

a+b+c = 180° (sum of angles in triangle)

(168 -2x)° + (160 -x)° + (172-x)° = 180°

500 -4x = 180

500-180 = 4x

320 = 4x

x = 320/4

x = 80°

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Answer:

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Step-by-step explanation:

From the question we are told

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Generally the pooled sample proportion is mathematically represented as

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Generally the test statistics is mathematically represented as

$z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2} ]} }$

=> $z = \frac{ 0.1315 - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688} ]} }$

=> $z = -1.56$

Generally the p-value is mathematically represented as

$p-value = P(z < -1.56 )$

From z-table

$P(z < -1.56 ) = 0.05938$

$p-value = 0.05938$

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