Question

HI = 3.9 and HJ = 6.2. Find IJ

Answer 1

Answer:

Part 1) $IJ=2.3\ units$

Part 2) $HJ=12\ units$

Part 3) $HJ=0.75\ units$

Part 4) $IH=4.7\ units$

Step-by-step explanation:

Part 1) HI = 3.9 and HJ = 6.2. Find IJ

we have that

I is between H and J

$HJ=HI+IJ$

substitute the given values and solve for IJ

$6.2=3.9+IJ$

subtract 3.9 both sides

$6.2-3.9=IJ$

$2.3=IJ$

Rewrite

$IJ=2.3\ units$

Part 2) JI = 25 and HI = 13. Find HJ

we have that

H is between I and J

$IJ=IH+HJ$

remember that

IH=HI  and IJ=JI

substitute the given values and solve for HJ

$25=13+HJ$

subtract 13 both sides

$25-13=HJ$

$12=HJ$

Rewrite

$HJ=12\ units$

Part 3) H is the midpoint of IJ and IH = 0.75. Find HJ

we have that

H is between I and J and H is the midpoint  of IJ

so

$IJ=IH+HJ$

$IH=HJ$ ----> because H is the midpoint

we have

$IH=0.75\ units$

therefore

$HJ=0.75\ units$

Part 4) H is the midpoint of IJ and IJ = 9.4. Find IH

we have that

H is between I and J and H is the midpoint  of IJ

so

$IJ=IH+HJ$ -----> equation A

$IH=HJ$ ----> equation B

substitute equation B in equation A

$IJ=2(IH)$

substitute the given value and solve for IH

$9.4=2(IH)$

Divide by 2 both sides

$IH=4.7\ units$