Question

Factor x^2-8x-48 completely

Answer 1

Answer: (X-12)(x+4)

The middle number is -8 and the last number is -48.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -8

Multiply together to get -48

Can you think of the two numbers?

Try 4 and -12:

4+-12 = -8

4*-12 = -48

Fill in the blanks in

(x+_)(x+_)

with 4 and -12 to get...

(x+4)(x-12)

Answer:

(x+4)(x−12)

Answer 2

$\implies {\blue {\boxed {\boxed {\purple {\sf { (x - 12)(x + 4 )}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

${x}^{2} - 8x - 48$

$= {x}^{2} + 4x - 12x - 48$

Taking $x$ as common from first two terms and $12$ from last two terms, we have

$= x \: (x + 4) - 12 \: (x + 4)$

Taking the factor $(x+4)$ as common,

$= (x - 12)(x + 4)$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$