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BabaBlast [244]
3 years ago
8

Write 3 decimals between 5.417 and 5.418 in Order from least to greatest

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0
Three decimals:
5.414
5.415
5.416

Ordered decimals:
5.414,5.415,5.416,5.417,5.418


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A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression. How many people clicked on the banner ad
wolverine [178]

Answer:

300

Step-by-step explanation:

\frac{1.5}{100} = 20000 \\ 20000 \div 100 = 200 \\ 200 \times 1.5 = 300

6 0
2 years ago
Expand logarithms equation
Bess [88]

Answer:

log_2(x) + log_2(y) + log_2(z)

Step-by-step explanation:

5log_2(xyz)^{1/5}\\\\5log_2(x)^{1/5} + 5log_2(y)^{1/5} + 5log_2(z)^{1/5}\\\\log_2(x) + log_2(y) + log_2(z)

4 0
3 years ago
Pls help trigonometry ahhh
oksano4ka [1.4K]

Answer:

x = 6.928

Step-by-step explanation:

Since we don't know the hypotenuse, we will use tan

tanΘ = opposite/adjacent     (Θ = theta, which is basically the variable for an angle)

tan30° = x/12

to find x, multiply 12 to the other side

12tan30° = x            (plug this into a calculator)

x = 6.928

5 0
3 years ago
Two vertices of a polygon are ( 7, -18) and (7, 18). What is the length of this side of the polygon?
Scilla [17]
Because the two vertices have the same x-coordinate, the side is a vertical line. It starts vertically from -18 to 18

the length = 18 - (-18)
the length = 18 + 18
the length = 36

The length of the side is 36 unit
8 0
3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
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