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klasskru [66]
3 years ago
13

Is 1620 divisible by 2,3,5,6,9,10

Mathematics
2 answers:
Zepler [3.9K]3 years ago
4 0
Yes it is devisible by all of thoughs #'s
777dan777 [17]3 years ago
4 0

Answer:

Yes, 1620 is divisible by 2,3,5,6,9,10

Step-by-step explanation:

we have to find the numbers out of 2,3,5,6,9,10 which divides 1620

1620= 2×2×3×3×3×3×5

Clearly from  the prime factorization of 1620, we can see that 1620 is divisible by 2,3 and 5

also, it is divisible by 2×3=6

also by 3×3=9

and 2×5=10

Hence, 1620 is divisible by 2,3,5,6,9,10

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Graph f(x)=3x-1 and g(x)=2^x on the same coordinate plane.
julsineya [31]

Answer:

B. 1 and D. 3.  

Step-by-step explanation:

The figure below shows the graphs of f(x) = 3x - 1 (red) and g(x) = 2^x (blue).

The solutions of 3x - 1 = 2^x are the points at which the two curves intersect.

The solutions are at x = 1 and x = 3.

Check:

3 × 1 - 1 = 2¹     3 × 3 -1 = 2³

    3 - 1 = 2           9 - 1 = 8

        2 = 2                8 = 8

7 0
4 years ago
Rewrite the expression using grouping symbols 13x - 29x
zhenek [66]
Does it mean factor it out??
x (13-29)
3 0
4 years ago
PLEASE HELP n+5(-n+1)=7
yKpoI14uk [10]

Answer: n= -1/2

Step-by-step explanation:

4 0
3 years ago
Holly wants to save money for an emergency. Holly invests 1,500 in an account that pays an interest rate of 6.75%. How many year
lina2011 [118]
The formula is
A=p (1+r)^t
A future value 7300
P present value 1500
R interest rate 0.0675
T time?
7300=1500 (1+0.0675)^t
Solve for t
Divide both sides by 1500
7300/1500=1.0675^t
Take the log for both sides
Log (7300/1500)=t×log (1.0675)
Divide both sides by log (1.0675)
T=log(7,300÷1,500)÷log(1.0675)
T=24.2 years round your answer to get 24 years

Hope it helps!
4 0
4 years ago
Read 2 more answers
The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
4 years ago
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