Answer:
It is proved that
.
Step-by-step explanation:
We already have the identity of x as
.......... (1) .
So, from equation (1) we can write that

⇒ 
⇒ 
⇒
Hence, it is proved that
. (Answer)
Answer: - 32
Step-by-step explanation:
-8 + (-24)
Infront of the Positive is a one.
-8 +1 (-24)
If we follow order of operations which is parentheses, exponents, multiply divide, add, and subtract, we can see we need to multiply/ distribute first. And a positive times a negative is a negative.
-8 -24
Now we put the two numbers together.
-32
This is the answer
A system is inconsistent when there are no solutions between the two equations. Graphically, the lines will be parallel (they never meet!) and the slopes will be the same. But the y-intercepts will be different.
Let's look at the four equations, with each solved as needed, into y = mx + b form.
A: 2x + y = 5
y = 5 - 2x
y = -2x + 5
Compared to y = 2x + 5, the slopes are different, so this system won't be inconsistent. Not a good choice.
B: y = 2x + 5
Compared to y = 2x + 5, the slopes are the same and the y intercepts are the same. This system has infinitely many solutions. Not a good choice.
C: 2x - 4y = 10
-4y = 10 - 2x
-4y = -2x + 10
y = 2/4x -10/4
Here the slopes are different, so, like A this is not a good choice.
D: 2y - 4x = -10
2y = =10 + 4x
2y = 4x - 10
y = 2x - 5
Compared to y = 2x + 5 we have the same slopes and different y intercepts. The lines will be parallel and the system is inconsistent.
Thus, D is the best choice.
Answer: the mass of a neutron is approximately 2,000 times the mass of an electron
Step-by-step explanation:
- the easiest way to solve this (in my opinion) is to simply divide the mass of a neutron by the mass of an electron
- 
= 
= 
≈ 
≈ 
≈ which is approximately 2222
- so 2222 is approximately 2000 times
- therefore, the mass of a neutron is approximately 2,000 times the mass of an electron
hope this helps :)
Solution:
we are given that
A student has some $1 and $5 bills in his wallet.
Let there x $1 bills and y number of $5 bills.
He has a total of 14 bills that are worth $34.
So we can write


Now solve these two equations together using substitution as follows

Hence there are 9 $1 bills and 5 bills are of $5.