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-Dominant- [34]
2 years ago
12

What equation in slope-intercept form represents the line that passes

Mathematics
1 answer:
4vir4ik [10]2 years ago
4 0

Answer:

2y = x - 7

Step-by-step explanation:

The general equation of the line is;

y = mx + b

where m is the slope and b is the y-intercept

To get the slope, we use the slope formula

m = (y2-y1)/(x2-x1)

(x1, y1) = (3,-2)

(x2,y2) = (1,-3)

m = (-3+2)/(1-3) = -1/-2 = 1/2

So we have the equation as;

y = x/2 + b

Multiply through by 2

2y = x + 2b

To get the y-intercept value, we substitute any of the points

Let us use the first point

While 3 will go for x , -2 will go for y; thus we have;

2(-2) = 3 + 2b

-4 = 3 + 2b

2b = -4-3

2b = -7

b = -7/2

So the equation is;

2y = x -7

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ppositional angle closure in eyes with narrow angles: comparison between the fellow eyes of acute angle-closure glaucoma and nor
skad [1K]

Here is the comparision

Purpose:To compare the topologic features of acute primary angle-closure glaucoma eyes before an attack to those of normotensive eyes, assuming that untreated fellow acute primary angle-closure glaucoma eyes are candidates for an acute attack.

Methods:Under dark-room conditions, ultrasound biomicroscopy was used to examine 50 eyes (12 fellow eyes of acute primary angle-closure glaucoma and 38 normotensive cases with a closure-possible narrow angle). Before any surgical or laser intervention, all eyes were examined and found to have normal pupillary response without the use of any topical drugs. Each eye was examined at four predetermined angle locations. The chamber angle configuration parameters were measured and compared between the two groups.

Result:Appositional angle closures were detected in 27 fellow eyes and 48 normotensive eyes with a closure-possible narrow angle. The incidence differed statistically between the two groups (69.2% in fellow eyes and 48% in normotensive eyes). In the fellow eye group, appositional angle closures beginning at the angle's entrance were more frequently detected. The distance between the iris root and the bottom of the angle varied significantly between groups.

Conclusion:Acute primary angle-closure glaucoma fellow eyes have different topologic features than normotensive narrow-angled eyes, as well as a higher incidence of appositional closure, which may predispose these eyes to an impending acute attack.

Learn more about glaucoma here:

brainly.com/question/1318395

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8 0
1 year ago
What is 1.8 - (-3.25)
malfutka [58]

Answer:

5.05

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
In parallelogram ABCD below, line AC is a diagonal, the measure of angle ABC is 40 degrees, and the measure of angle ACD is 57 d
Lorico [155]

Answer:

The measure of angle CAD is 83 degrees.

Step-by-step explanation:

Given information: ABCD is a parallelogram, AC is a diagonal, \angle ABC=40^{\circ} and  \angle ACD=57^{\circ}.

The opposite sides of parallelogram are congruent.

The diagonal AC divides the parallelogram in two congruent triangles.

In triangle ABC and ADC,

AB\cong CD                                     (Opposite sides of parallelogram)

\angle ABC\cong \angle ADC         (Opposite angles of parallelogram)

BC\cong DA                                     (Opposite sides of parallelogram)

By SAS postulate,

\triangle ABC\cong \triangle CDA

Since we know that opposite angles of parallelogram are equal, therefore

\angle ABC\cong \angle ADC

\angle ADC=40^{\circ}

According to the angle sum property the sum of interior angles of a triangle is 180 degrees.

\angle CAD+\angle ACD+\angle ADC=180^{\circ}

\angle CAD+57^{\circ}+40^{\circ}=180^{\circ}

\angle CAD=83^{\circ}

Therefore the measure of angle CAD is 83 degrees.

6 0
2 years ago
9 increased by 6 can be stated as the total of 9 and 6
denis23 [38]

9 increased by 6 can be stated as the total of 9 and 6 is completely possible because:

  • 9 increased by 6: 9 + 6 = 15
  • Total of 9 and 6 = 15

Since both provide the same answer the statement is true.


Hope it helps :)

4 0
3 years ago
fred purchased a new car for $53,000. the car depreciates 17% of its value each year compounded continuously. how much is it wor
Zepler [3.9K]

Answer:

It is worth $26,855 after 5 years

Step-by-step explanation:

53000 ÷ (1 + .17 ÷ 365)^(365 × 4)

8 0
2 years ago
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