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3 years ago

Prime integers between 1and11

Mathematics

1 answer:

Roman55 [17]3 years ago

5 0

Answer:

1,3,5,7,11

Step-by-step explanation:

a prime numb er or integer is a number that can not be multiplied to get to other than x1 so for example the only thing you can do for 3 is 3x1 not anything else especially because you said integer

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Simplify the expression.<br> (2i^16)^3 x – 5i^7

Hunter-Best [27]

Answer:

8x+5i

Step-by-step explanation:sorry if its wrong

6 0

3 years ago

Hey can you please help me posted picture of question

GalinKa [24]

The given equation is:
ax2 + bx + c = 0
We have the resolvent is:
x = (- b +/- root (b2 - 4ac)) / (2a)
The discriminant is:
b2 - 4ac = 0
The solution will be:
x = (- b) / (2a)
Thus, the equation has a real solution.
Answer:
option B

5 0

3 years ago

An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

neonofarm [45]

Answer:

There is a 33.10% probability that there is at least one defective integrated circuit.

Step-by-step explanation:

For either integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

The electonic product contains 40 integrated circuits, so $n = 40$ .

The probability that any integrated circuit is defective is 0.01, so $\pi = 0.01$

What is the probability that there is at least one defective integrated circuit?

Either there is at least one defective integrated circuit, that is probability $P(X > 0)$ , or there are no defective integrated circuits, that is probability $P(X = 0)$ . The sum of these probabilities is decimal 1. We want to find $P(X>0)$ .

$P(X > 0) + P(X = 0) = 1$

$P(X > 0) = 1 - P(X = 0)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{40,0}.(0.01)^{0}.(0.99)^{40} = 0.6690$

$P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310$

There is a 33.10% probability that there is at least one defective integrated circuit.

3 0

3 years ago

Read 2 more answers

ANSWER ASAP!! MORE THAN ONE

GrogVix [38]

The answer is 8 + x > 5An equation or an inequality that contains at least one variable is called an open sentence.
When you substitute the variable in an open sentence with a number the resulting statement is either true or false. If the statement is true the number is a solution to the equation or inequality.

7 0

3 years ago

What is the distance in units between the points (8,-1) and (-2,-1) on a coordinate plane?

Sliva [168]

You can use the distance formula.
The distance formula says the distance between two given points (x1, y1) and (x2, y2)
= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

Your given points are (8, -1) and (-2, -1).
The distance will be
$\sqrt{(-1+1)^2+(-2-8)^2} \\ = \sqrt{100} \\ =10$ .

But you could have recognized that both points have the same y-coordinate of -1, which means change in distance is determined by change in x-coordinates only.
Change in x-coordinates is |-8 - 2| = 10. There is absolute value because distance cannot be negative.

3 0

3 years ago

Prime integers between 1and11​

Prime integers between 1and11