To find the total length we justadd the llength of the vBulletin peices together 9 +5.59 + 16 . 8 = 31.39
The total length is 31.39
Answer:
y= 19.5 x=33
Step-by-step explanation:
-x + 27= -6
(subtract 27 on both sides)
-x= -33
(divide by negative 1 on both sides)
x= 33
(substitute x into the first equation)
y= 1/2x + 3
y= 1/2(33) +3
y= 16.5 +3
y= 19.5
hope this helps :))
Answers:
- x = 10
- angle CAT = 126 degrees
- angle MUD = 54 degrees
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Explanation:
∠CAT and ∠MUD are supplementary, which means the angle measures add to 180. They form a straight line.
( m∠CAT ) + ( m∠MUD ) = 180
( 11x+16 ) + ( 4x+14 ) = 180
11x+16 + 4x+14 = 180
(11x+4x) + (16+14) = 180
15x+30 = 180
15x = 180-30
15x = 150
x = 150/15
x = 10
Let's find each angle based on this x value
- m∠CAT=11x+16 = 11*10+16 = 110+16 = 126 degrees
- m∠MUD=4x+14 = 4*10+14 = 40+14 = 54 degrees
Those two angles add to 126+54 = 180 to confirm we do indeed have supplementary angles, and confirm the correct answers.
Answer and explanation:
The gambler's fallacy is the fallacy of belief that if an event such as a loss occurs more frequently in the past, it is less likely to happen in the future. We assume here that this belief is true, therefore
If she loses, her probability of winning increases =3/4
If she wins, her probability to win is normal =1/2
Given that probability of winning is 1/2
Probability of losing is 1-1/2=1/2
Probability that she wins the tournament is probability that she wins the first two games and loses the last or wins the first game, loses the second and wins the last or loses the first game and wins the last two games or probability that she wins all three games
=1/2*1/2*1/2+1/2*1/2*3/4+1/2*3/4*1/2+1/2*1/2*1/2
=25/48
Probability of winning the tournament if she loses the first game
=1/2*3/4*1/2= 3/16
Note: whenever there is "or" in probability, you add
Answer:
x^2 + y^2 + 16x + 6y + 9 = 0
Step-by-step explanation:
Using the formula for equation of a circle
(x - a)^2 + (y + b)^2 = r^2
(a, b) - the center
r - radius of the circle
Inserting the values given in the question
(-8,3) and r = 8
a - -8
b - 3
r - 8
[ x -(-8)]^2 + (y+3)^2 = 8^2
(x + 8)^2 + (y + 3)^2 = 8^2
Solving the brackets
( x + 8)(x + 8) + (y +3)(y+3) = 64
x^2 + 16x + 64 + y^2 + 6y + 9 = 64
Rearranging algebrally,.
x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0
Bringing in 64, thereby changing the + sign to -
Therefore, the equation of the circle =
x^2 + y^2 + 16x + 6y + 9 = 0
