Answer:
6x^2 -4x +8
Step-by-step explanation:
(6x^2 + 5) - (4x - 3)
Distribute the negative sign
(6x^2 + 5) - 4x + 3
Combine like terms
6x^2 -4x +5+3
6x^2 -4x +8
Answer:
n(t) = 10×1.2^t
Step-by-step explanation:
The idea here is that the number of ill students is multiplied by 1+20% = 1.20 each hour. That is, after t hours, you have multiplied the original number by 1.20 "t" times. Of course, repeated multiplication is signified using an exponent.
The form you can use in such cases is ...
value = (initial value)×(growth factor in period)^(number of periods)
Here, you're given a growth rate (20% per hour), so you add 1 to get the growth factor (as we showed above).
Your exponential function can be ...
n(t) = 10×1.20^t
Answer:
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Step-by-step explanation:
tu, se vuoi puoi venire in mente, ma 9 69
The perimeter is.just.the.sides.added.up
6+6+20+28=60
for the area add up the area of the rectangle 20(5)=100 plus the areas of the triangles 4(5)=20
total area = 120
(a) Let denote the amount of sugar in the tank at time . The tank starts with only pure water, so .
(b) Sugar flows in at a rate of
(0.07 kg/L) * (7 L/min) = 0.49 kg/min = 49/100 kg/min
and flows out at a rate of
(<em>A(t)</em>/1080 kg/L) * (7 L/min) = 7<em>A(t)</em>/1080 kg/min
so that the net rate of change of is governed by the ODE,
or
Multiply both sides by the integrating factor to condense the left side into the derivative of a product:
Integrate both sides:
Solve for :
Given that , we find
so that the amount of sugar at any time is
(c) As , the exponential term converges to 0 and we're left with
or 75.6 kg of sugar.