The volume of the box is
.. V = (90 cm)*(45 cm)*(45 cm) = 182,250 cm³
The empty 15% of the volume is then
.. empty volume = 0.15*182,250 cm³ = 27,337.5 cm³
This will require
.. (empty volume)/(volume / bag) = 27,337.5 cm³ / (28,316 cm³/bag) ≈ 0.97 bag
to fill.
Selection A. 1 bag is appropriate.
Answer:
Step-by-step explanation:
Given: Number of cards a box contains = 10 (numbered 1 through 10).
A random card is picked at first instance and is denoted X and then another card is picked from remaining cards and is denoted as Y
Here E(X) = (1+2+3+4+5+6+7+8+9+10)/10 = 5.5
E(Y)=P(X=1) *E(Y|X=1) +P(X=2) *E(Y|X=2) +. .+P(X=10)*E(Y|X=10)
= (1/10) *(2+3+4+ .+10)/9+(1/10)*(1+3+4+..+10)/9+....+(1/10)*(1+2+3+4+5...+9)/9
= (1/10) *(9/9) *(1+2+3+4+5+6+7+8+9+10) = 5.5
Hence, E(X-Y) = E(X) - E(Y) = 0.000
