This won’t take long please look at it

Oxygen flows through one tube into a liter flask filled with air, and the mixture of oxygen and air (considered well stirred) es

yKpoI14uk [10]

The amount of oxygen in the flask through the intake tube illustrates proportions

The flask 99.35% will contain of oxygen after 5L have passed through the intake tube

<h3>How to calculate the percentage of oxygen?</h3>

To do this, we make use of the following representations

P for the proportion of oxygen
V for te volume of oxygen
x for the proportion of oxygen in the flask after 5 L passed through

So. we have the following derivative

dP = dV - P * dV

Divide through by dV

dP/dV = 1 - P

Next, we set up the integral

$\int\limits^x_{0.040} \frac {1}{1 - P}dP= \int\limits^5_0 {dV}$

Integrate both sides

$-\ln(|P - 1|)|\limits^x_{0.04} = 5$

Expand

-ln(|x - 1|) + ln(|0.04 - 1|) = 5

Evaluate the difference

-ln(|x - 1|) + ln(|-0.96|) = 5

Express as a fraction

ln(0.96/|x - 1|) = 5

Express both sides as exponents with a base of 2

e^ln(0.96/|x - 1|) = e^5

Solve for x

x = 1 - 0.96/e^5

Evaluate the difference

x = 0.9935

Express as percentage

x = 99.35%

Hence, the flask 99.35% will contain of oxygen after 5L have passed through the intake tube

Read more about proportions at:

brainly.com/question/1781657

3 0

2 years ago

The automobile assembly plant you manage has a Cobb-Douglas production function given by p = 10x^0.2 y^0.8

Zepler [3.9K]

Answer:

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

This value of Δy is not constant for a constant increase in production.

Step-by-step explanation:

We know that the production function is $p = 10x^{0.2} y^{0.8}$ , and in the current situation $p=1200$ and $x=130$ .

With this information we can calculate the actual budget level:

$p_0 = 10x^{0.2} y^{0.8}\\\\1200=10*130^{0.2} y^{0.8}\\\\1200=26.47*y^{0.8}\\\\y=(1200/26.47)^{1/0.8}=45.33^{1.25}=117.62$

The next year, with an increase in demand of 100 more automobiles, the production will be $p_1=1300$ .

If we calculate y for this new situation, we have:

$y_1=(\frac{p_1}{10x^{0.2}} )^{1.25}=(\frac{1300}{26.47} )^{1.25}=49.10^{1.25}=130$

The budget for the following year is 130.

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

$\Delta y=y_1-y_0=130.00-117.62=12.38$

This value of Δy is not constant for a constant increase in production.

3 0

3 years ago

A parking lot is 20 feet long. One tortoise starts at the edge of the parking lot and moves at a rate of 6 feet per minute. Anot

anygoal [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Length of parking lot = 20 feets

Speed of tortoise which starts at the edge = 6 feets per minute

Speed of tortoise which starts 4 feets from the edge = 2 feets per minute

Equation to represent when they will be in the same spot.

Distance = speed * time

Distance of Tortoise at edge = 6ft/min * t = 6t - - (1)

Distance of the other tortoise = (4 + 2t) - - - (2)

Equating both (1) and (2)

6t = 4 + 2t

6t - 2t = 4

4t = 4

t = 4/4

t = 1

Hence, they'll be at the same spot after 1 minute.

6 0

3 years ago

community group bought 30 tickets to an amusement park at a total cost of $810. They bought x student tickets for $25 each and y

Zina [86]

it would be 18 student tickets and 12 adult tickets

18x25= 450

12x30 = 360

360+450 = 810

4 0

3 years ago

if a store is offering 20% discount on all items. is there a proportional relationship between the original price of an item and

Novosadov [1.4K]

Answer:

A store is offering a 14% discount on all items. Write an equation relating the sale price S for an item to its list price L.

Step-by-step explanation:

8 0

3 years ago