A. nine hundredths
B. Thirty five hundredths
C. Seven Tenths
D. Three Thousandths
E. One Hundred Fourty five Thousandths
F. Fifty Nine Ten Thousandths
Hi sam, do you want to know the answer? Try using a protractor, you will see the degree is 125, its like a obtuse angle
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
the one that starts with (-2,-2)
Answer:
5 folders and 5 pens = yes
6 pens and 6 erasers = yes
1 pen and 4 notebooks = no
3 folders and 7 erasers = no
4 folders and 2 notebooks = yes
Step-by-step explanation:
Max total = $10
(5 folders x 1.29) + (5 pens x 0.70)
6.45 + 3.50 = 9.95
(6 pens x 0.70) + (6 erasers x 0.89)
4.20 + 5.34 = 9.54
(1 pen × 0.70) + (4 notebooks × 2.35)
0.70 + 9.40 = 10.10
(3 folders × 1.29) + (7 erasers × 0.89)
3.98 + 6.23 = 10.21
(4 folders × 1.29) + (2 notebooks × 2.35)
5.16 + 4.70 = 9.86
