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3 years ago

Find the slope of the line that passes through the points (1,10) and (-8,3)

Mathematics

1 answer:

dem82 [27]3 years ago

3 0

We can use the points (1, 10) and (-8, 3) to solve.

Slope formula: y2-y1/x2-x1

= 3-10/-8-1

= -7/-9

= 7/9

Best of Luck!

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A sequence is defined recursively by the formula f(n + 1) = –2f(n). The first term of the sequence is –1.5. What is the next ter

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Answer:

Step-by-step explanation:

Put the given numbers in the formula and do the arithmetic.

f(2) = -2·f(1) = -2·(-1.5) = 3

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Read 2 more answers

Can anyone answer me this question

yuradex [85]

Question 1:

For this case we have the following functions:

$f (x) = 4x + 1\\g (x) = x ^ 3 + 1$

We must find $g_ {o} f (0$ ):

By definition we have to:

$g_ {o} f = g (f (x))\\f_ {o} g = f (g (x))$

$g (f (x)) = (4x + 1) ^ 3 + 1$

We substitute $x = 0$ :

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So, we have that $g (f (0)) = 2$

Answer:

$g (f (0)) = 2$

Question 2:

For this case we have the following functions:

$f (x) = 4x + 1\\g (x) = x ^ 3 + 1$

We must find $f_ {o} g (0)$ :

By definition we have to:

$f_ {o} g = f (g (x))\\f (g (x)) = 4 (x ^ 3 + 1) + 1 = 4x ^ 3 + 4 + 1 = 4x ^ 3 + 5$

We substitute $x = 0$ :

$f (g (0)) = 4 (0) ^ 3 + 5 = 5$

Answer:

$f (g (0)) = 5$

Question 3:

For this case we must find the inverse of the following function:

$h (x) = \frac {2x + 1} {3}$

To do this, we follow the steps below:

We change y for $h (x)$ :

$y = \frac {2x + 1} {3}$

We exchange variables:

$x = \frac {2y + 1} {3}$

We clear the value of the variable "y":

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We change y for $h^{ -1} (x)$ :

$h ^{ - 1} (x) = \frac {3x} {2} - \frac {1} {2}$

Answer:

$h ^ {- 1} (x) = \frac {3x} {2} - \frac {1} {2}$

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