Question

Somebody help please​

Answer 1

Answer:

$\frac{2(a+4b)}{a^2 -b^2 }$

Step-by-step explanation:

$\frac{3}{a-b} -\frac{1}{a+b} +\frac{4b}{(a-b)(a+b)}$ =

$\frac{3(a+b)}{(a-b)(a+b)} -\frac{a-b}{(a-b)(a+b)} +\frac{4b}{(a-b)(a+b)}$ =

$\frac{3a + 3b -a + b + 4b}{(a-b)(a+b)}$ =

$\frac{2(a+4b)}{a^2 -b^2 }$

Answer 2

Answer: look at the picture i attached!