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3 years ago

Somebody help please

Mathematics

2 answers:

lozanna [386]3 years ago

6 0

Answer:

$\frac{2(a+4b)}{a^2 -b^2 }$

Step-by-step explanation:

$\frac{3}{a-b} -\frac{1}{a+b} +\frac{4b}{(a-b)(a+b)}$ =

$\frac{3(a+b)}{(a-b)(a+b)} -\frac{a-b}{(a-b)(a+b)} +\frac{4b}{(a-b)(a+b)}$ =

$\frac{3a + 3b -a + b + 4b}{(a-b)(a+b)}$ =

$\frac{2(a+4b)}{a^2 -b^2 }$

inessss [21]3 years ago

3 0

Answer: look at the picture i attached!

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The shaded region is a parallelogram.

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The base of the parallelogram is 2 meters long (given).

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The height is 9 meters because the height has to be perpendicular to the base. Thus, the side length must be 9 meters.

Multiply them together.

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4 years ago

There are 36 students playing tag at recess. This is 6 times more the hopscotch.

barxatty [35]

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3 years ago

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What is 5×=2.5<br><br>please help

marissa [1.9K]

Answer:

x=2/5

Step-by-step explanation:

Divide:

2 divided by 5 equals 0.4, which is equivalent to 4/10, which simplifies to 2/5.

Multiply to check:

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3 years ago

HELP, IT'S URGENT SO PLEASE REPLY QUICKLY!

ehidna [41]

b. 39.74

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4 years ago

State the vertical asymptote of the rational function. f(x) =((x-9)(x+7))/(x^2-4)

Lubov Fominskaja [6]

$D:x^2-4\not=0\\
D:x^2\not=4\\
D:x\not=-2 \wedge x\not =2\\\\
\displaystyle
\lim_{x\to-2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(-2-9)(-2+7)}{(-2^-)^2-4}=\dfrac{-11\cdot5}{4^+-4}=\dfrac{-55}{0^+}=-55\cdot\infty=-\infty\\
\dfrac{(-2-9)(-2+7)}{(-2^+)^2-4}=\dfrac{-11\cdot5}{4^--4}=\dfrac{-55}{0^-}=-55\cdot(-\infty)=\infty
$

$\displaystyle
\lim_{x\to2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(2-9)(2+7)}{(2^-)^2-4}=\dfrac{-7\cdot9}{4^--4}=\dfrac{-63}{0^-}=-63\cdot(-\infty)=\infty\\
\dfrac{(2-9)(2+7)}{(2^+)^2-4}=\dfrac{-7\cdot9}{4^+-4}=\dfrac{-63}{0^+}=-63\cdot\infty=-\infty\\$

So, the vertical asymptotes are $x=\pm 2$

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4 years ago

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Somebody help please​

Somebody help please