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-Dominant- [34]
3 years ago
13

What is the interquartile range of this data? 6 8 9 20

Mathematics
2 answers:
givi [52]3 years ago
6 0

Answer:

20

Step-by-step explanation:

The interquartile range is the difference between the values of the upper quartile and the lower quartile.

The upper quartile is the value at the right side of the box, that is 36

The lower quartile is the value at the left side of the box, that is 16

Interquartile range = 36 - 16 = 20

KengaRu [80]3 years ago
5 0

Answer:

20

Step-by-step explanation:

36 - 16 = 20

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Step-by-step explanation:

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

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Use the Volume of a Cylinder formula and the given values to find the <u>radius of the cylinder</u>:

\implies \sf 1715=\pi r^2 (18)

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<u>Surface Area of a Cylinder</u>

\sf SA=2 \pi r^2 + 2 \pi r h \quad\textsf{(where r is the radius and h is the height)}

Substitute the given value of h and the found value of r into the formula and solve for SA:

\implies \sf SA=2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)^2 + 2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)(18)

\implies \sf SA=2 \pi \left(\dfrac{1715}{18 \pi} \right) + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)

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