1.) The error is that she attached the
variable with the flat fee (which is
constant) and put the daily rent as a
constant (which is variable).
The correct equation is:
365+125x=250+175x
2.) N=5
3.) k=-35.
Explanation: Solution:
17k-6=37k+4 . 17k-37k=4+6 .
-27k=10 . k=10\cdot(7-2) . k=-35 .
4.)
.
Answer:
Yes the ordered dose of 200 mg/d lies within the recommended range of 75 mg/d to 375 mg/d
Step-by-step explanation:
Given:
Ordered dose of Anadrol-50 (oxymetholone) = 200 mg per day
Recommended range = 1-5 mg/kg/d
Weight of the patient = 75 kg
Now,
For the patient weighing 75 kg, the recommended dose will be
Minimum dose will be
= Minimum value of Recommended range × Weight of the patient
= 1 mg/kg/d × 75 kg
= 75 mg/d
and,
the Maximum dose will be
= Maximum value of Recommended range × Weight of the patient
= 5 mg/kg/d × 75 kg
= 375 mg/d
Yes the ordered dose of 200 mg/d lies within the recommended range of 75 mg/d to 375 mg/d
<u>Option A)</u> when y=6 and w= 2, <u>Option B)</u> when y=4 and w=-1 are the TWO correct choices.
Step-by-step explanation:
The given inequality is w<x<y and x>2.
<u>step 1</u>: let us <u>assume that x=3</u>, since it is given that x>2.
<u>step 2</u>: substitute the value of x=3 and each options in the inequality
<u>step 3</u>: option A) w=2, y=6. Then w<x<y = 2<3<6 (the condition satisfies).
option B) w= -1, y=4. Then w<x<y = -1<3<4 (the condition satisfies).
option C) w= 0, y=2. then w<x<y ≠ 0<2<2 (does not satisfies).
option D) w= -2, y=0. then w<x<y ≠ -2<2<0 (does not satisfies).
option E) w= -4, y= -1. then w<x<y ≠ -4<2<-1 (does not satisfies).
Given:
mean, μ = 11 lb
Std. deviation, σ = 2.1
Let x = the weight that separates the top 5% of the crop.
The z-score is
z = (x - μ)/σ
= (x - 11)/2.1
From standard z-table for normal distribution,
P(z=1.645) = 0.95
Therefore
(x - 11)/2.1 = 1.645
x - 11 = 1.645/2.1 = 0.7833
x = 11.783
Answer: 11.8 lb (nearest tenth)
