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kiruha [24]
3 years ago
9

What is the solution to the system of equations? Use the substitution method.

Mathematics
1 answer:
Sav [38]3 years ago
4 0
THE solution is D.


you have 7 and 3 so commom multiple is 21
y-3*7=7

y-21=7

y=21+7

y=28
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Convert 55° 16' 30" into radian measure.​
Colt1911 [192]

Answer:

55° 16' 30" = 0.9648 radians .

Step-by-step explanation:

8 0
3 years ago
What is the solutions to the equation w/2w-3=4/w
labwork [276]

Answer:

{2, 6}

Step-by-step explanation:

w/2w-3=4/w  is ambiguous.  Did you mean

   w            4

---------- = ------     ?  If so, please enclose "2w - 3" inside parentheses.

2w - 3       w

Cross multiplying, we get w² = 8w - 12.

Putting this into standard form, we get:

w² - 8w + 12 = 0, which factors into (w - 2)(w - 6) = 0.

The solutions are found by setting each factor = 0 separately and solving the resulting equations for w:  {2, 6}.

7 0
3 years ago
One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 510,
Brums [2.3K]

Answer:

82

Step-by-step explanation:

solve a + (3a) + (a + 100)=510

7 0
3 years ago
The ice cream shop offers 31 flavors. you order a double scoop cone how many different ways can the clerk put the ice cream on t
Lynna [10]

Answer:

465

Step-by-step explanation:

Since we are looking for the the number of combinations to have 2 different flavors in the ice cream, we can use the formula for combination.

_{n}C_{k}=\dfrac{n!}{k!(n-k)!}

Our variables are:

n = 31

k = 2

_{31}C_{2}=\dfrac{31!}{2!(31-2)!}

_{31}C_{2}=\dfrac{31!}{2!29!}

_{31}C_{2}=\dfrac{31!}{2!29!}

_{31}C_{2}=465

The number of possible combinations of having 2 different flavors out of 31 different flavors is 465.

6 0
3 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
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