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gizmo_the_mogwai [7]
3 years ago
9

Indicate which two quadrants “theta” could terminate if sin theta = 4/5

Mathematics
1 answer:
Nitella [24]3 years ago
8 0

Answer:

1st and 2nd quadrants

Step-by-step explanation:

You have sine is positive since it is 4/5.

Sine is the y-coordinate.

On the coordinate plane y is positive in the 1st and 2nd quadrants.

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What is the distance between (4,7) and (2,2)?
algol [13]
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 4}}\quad ,&{{ 7}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{(2-4)^2+(2-7)^2}\implies d=\sqrt{(-2)^2+(-5)^2}
\\\\\\
d=\sqrt{4+25}\implies d=\sqrt{29}
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7 0
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