Answer:
The answer is 126.
Step-by-step explanation:
If you multiply 2*9 first, you get 18. Then multiply 18 by 7. The answer will be 126. I hope this helps.
Hello!
Find the coordinate where x = -1:
At x = -1, y = 1, so the coordinate is (-1, 1).
Find the coordinate where x = 2:
At x = 2, y = -2, so the coordinate is (2, -2).
Find the rate of change between the points using the slope formula:
![slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=slope%20%3D%20%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
Plug in the coordinates above:
![slope = \frac{-2-1}{2-(-1)}](https://tex.z-dn.net/?f=slope%20%3D%20%5Cfrac%7B-2-1%7D%7B2-%28-1%29%7D)
Simplify:
Thus, the rate of change between the points is -1.
put the percentage on the right and label it "% of parents who use it "
and at the bottom of the graph, put " types of parental control"
count the percentages by five's starting from 25
then just fill in the shading
To solve the inequality ![\frac{x^2+x+3}{2x^2+x-6}\ge \:0](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%5E2%2Bx%2B3%7D%7B2x%5E2%2Bx-6%7D%5Cge%20%5C%3A0%20)
![\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:](https://tex.z-dn.net/?f=%20%5Cmathrm%7BFactor%5C%3Athe%5C%3Aleft%5C%3Ahand%5C%3Aside%5C%3A%7D%5Cfrac%7Bx%5E2%2Bx%2B3%7D%7B2x%5E2%2Bx-6%7D%3A%20)
The numerator
is not factorizable.
so factor the denominator
:
![2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\](https://tex.z-dn.net/?f=%202x%5E2%2Bx-6%3D%5Cleft%282x%5E2-3x%5Cright%29%2B%5Cleft%284x-6%5Cright%29%3Dx%5Cleft%282x-3%5Cright%29%2B2%5Cleft%282x-3%5Cright%29%5C%5C%20%5Cmathrm%7BFactor%5C%3Aout%5C%3A%7Dx%5Cmathrm%7B%5C%3Afrom%5C%3A%7D2x%5E2-3x%5Cmathrm%7B%3A%5Cquad%20%7Dx%5Cleft%282x-3%5Cright%29%5C%5C%20%5Cmathrm%7BFactor%5C%3Aout%5C%3A%7D2%5Cmathrm%7B%5C%3Afrom%5C%3A%7D4x-6%5Cmathrm%7B%3A%5Cquad%20%7D2%5Cleft%282x-3%5Cright%29%5C%5C%20%20)
Now take ![\mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)](https://tex.z-dn.net/?f=%20%5Cmathrm%7BFactor%5C%3Aout%5C%3Acommon%5C%3Aterm%5C%3A%7D%5Cleft%282x-3%5Cright%29%20)
Then we get factor of the denominator as ![\left(2x-3\right)\left(x+2\right)](https://tex.z-dn.net/?f=%20%5Cleft%282x-3%5Cright%29%5Cleft%28x%2B2%5Cright%29%20)
Thus ![\frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%5E2%2Bx%2B3%7D%7B2x%5E2%2Bx-6%7D%3D%5Cfrac%7Bx%5E2%2Bx%2B3%7D%7B%5Cleft%28x%2B2%5Cright%29%5Cleft%282x-3%5Cright%29%7D%20%20)
Now ![\mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\](https://tex.z-dn.net/?f=%20%5Cmathrm%7BCompute%5C%3Athe%5C%3Asigns%5C%3Aof%5C%3Athe%5C%3Afactors%5C%3Aof%5C%3A%7D%5Cfrac%7Bx%5E2%2Bx%2B3%7D%7B%5Cleft%28x%2B2%5Cright%29%5Cleft%282x-3%5Cright%29%7D%5C%5C%20)
Signs of ![x^2+x+3>0](https://tex.z-dn.net/?f=%20x%5E2%2Bx%2B3%3E0%20)
![\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0](https://tex.z-dn.net/?f=%20%5Cmathrm%7BChoosing%5C%3Aranges%5C%3Athat%5C%3Asatisfy%5C%3Athe%5C%3Arequired%5C%3Acondition%3A%7D%5C%3A%5Cge%20%5C%3A%5C%3A0%20)
is the required solution of the given inequality.
The sample space is {(1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T)}
On the number cube, she could roll any of the numbers from 1 to 6. On the coin, she could flip heads or tails.