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Oksanka [162]
3 years ago
10

What are the x- and y-intercepts of the graph of 5x-4y= -20

Mathematics
1 answer:
Zolol [24]3 years ago
8 0

Answer:

hello :

x- intercepts when x = 0 : -4y = -20   so : y = 5

y - intercepts when y = 0 : 5x = -20   so : x = -4




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Please help me im doing a math test and i don’t wanna fail :(
cricket20 [7]

Answer:

The scale factor of dilation is 2.25

Step-by-step explanation:

I just measured the base of Figure A. The base is 4 square units. The base of Figure B is 9 units. 4 x 2.25 = 9.

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6 0
3 years ago
Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
(-2) times (+5) times (-1) times (-5) times (-2)<br> please can u answer fast i have a test in 2 min
zlopas [31]

Answer:

100

Step-by-step explanation:

4 0
1 year ago
PLS HELP ME I WILL MARK THE BRAINLIEST
Serga [27]

Answer:

1. 155 yd², 2. 379.54 ft², 5. x = 65.82π

Step-by-step explanation:

1. A = (1/2) · (3 + 13) · 8

A = (1/2)(16)(8)
A = 64
A = bh
A = 13*7
A = 91
64 + 91 = 155
155 yd²

2. A = bh
A = 25x25
A = 625
A = πr²
A = 3.14*12.5²
A = 3.14*156.25
A = 490.625
490.925/2 = 245.4625
625 - 245.4625 = 379.5375
379.54 ft²

3. and 4. Sorry, I don't know how to solve these

5. A = πr²
A = 3.14*7²
A = 3.14*49
A = 153.86
x/154 = 153.86π/360
360x = 154*153.86π
360x = 23694.44π
x = 65.8178889π
x = 65.82π

Hope this helps :)

7 0
2 years ago
What is the inverse of f (x)=e^x+6
goldfiish [28.3K]
To find the inverse, switch the variables and solve for f(x).

x = e^f(x) + 6
x - 6 = e^f(x)
f(x) = ln(x-6)

hope this helps :)
8 0
3 years ago
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