Answer:
1st integer=x
2nd integer=x+1
3rd integer=x+2
4th integer=x+3
2(x +(x+2))= 3(x+1) +11
solve
2 (2x +2) = 3x + 3 + 11
4x + 4 = 3x + 14
-3x-4 =-3x -4
x=10
1st integer=10
2nd integer=11
3rd integer=12
4th integer=13
Step-by-step explanation:
hopefully this helped
Answer:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
b
= M
/4 + 9
x
Answer:
a - t = 2
Step-by-step explanation:
1) -3(5x+2y=-3)⇒ -15x-6y=9
⇒ -9x=27
2(3x+3y=9)⇒ 6x+6y=18
2) -9x/-9=27/-9 ⇒ x=-3
3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6
Answer: (-3,6)
Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.
Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em>
